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Evgesh-ka [11]
3 years ago
5

I need some help with this calculus 1 implicit diffrention problem?

Mathematics
1 answer:
katen-ka-za [31]3 years ago
7 0

Answer:

y" = -24 / y³

Step-by-step explanation:

6x² + y² = 4

Take the derivative of both sides with respect to x.

12x + 2y y' = 0

Again, take the derivative of both sides with respect to x.

12 + 2y y" + y' (2y') = 0

12 + 2y y" + 2(y')² = 0

Solve for y' in the first equation.

2y y' = -12x

y' = -6x/y

Substitute and solve for y":

12 + 2y y" + 2(-6x/y)² = 0

12 + 2y y" + 2(36x²/y²) = 0

12 + 2y y" + 72x²/y² = 0

6y² + y³ y" + 36x² = 0

y³ y" = -36x² − 6y²

y" = (-36x² − 6y²) / y³

Solve for y² in the original equation and substitute:

y² = 4 − 6x²

y" = (-36x² − 6(4 − 6x²)) / y³

y" = (-36x² − 24 + 36x²) / y³

y" = -24 / y³

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Answer:

If the reindeer do not fight, there are 5!=120 ways to line them up in a straight line.

Out of these, Bloopin and Rudy are together in 4!=24 times.  Similarly Rudy and Bloopin will be together 4!=24 times.  So the number of ways they are not together is 120-24-24=72 ways.

Hope this helps.    :)

Step-by-step explanation:

Spanish:

Si los renos no luchan, hay 5! = 120 formas de alinearlos en línea recta.

De estos, Bloopin y Rudy están juntos en 4! = 24 veces. De manera similar, Rudy y Bloopin estarán juntos 4! = 24 veces. Entonces, el número de formas en que no están juntas es 120-24-24 = 72 formas.

Espero que esto ayude       :)

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