Answer:
Option c is the correct answer for the above question.
Explanation:
- If the array will store in row-major order, then it will be a store like the first row, then second row and then third row.
- If the user wants to conclude the address of the A[3,5], then the address of the A[3,5] will be 184.
- It is because the 3 states the row number and the 5 states the column number.
- The above question states that every value take 8 bit. and there are 4 rows from 0 to 3 and 6 column (0 to 5) for every row (except the fourth rows because it takes 5 columns from 0 to 4) before the A[3,5].
- So there are 23 value before A[3,5] which are as-- [00,01,02,03,04,05][10,11,12,13,14,15][20,21,22,23,24,25][30,31,32,33,34].
- So when every value takes 8 bit then 23 value takes 184 bits(23*8).
- So the address of A[3,4] is 184.
- Hence option c is the correct and the other is not because of 184 stated from the c option only.
Answer:
The value EAX contain after the code has been executed is 1233
Explanation:
Solution
Now,
The below instruction describes the MOV operation.
The MOV esi, OFFSET idArray .
It shows the movement, the offset value of the idArray in the esi.
Thus,
Follow the below instruction
MOV eax, [esi+7*TYPE idArray]
It will move the address of the idArray at that position into eax.
Value at the 7th position is moved to eax.
Therefore, the value at eax will be 1233.
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Money market?? i think anyway.
