Two motorcyclist A and B, started simultaneously moving towards each other. From the graph given below, find the distance each o
f them covered, time before they meet, and the average speed of motorcyclists. (See graph)
1 answer:
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See the picture attached to better understand the problem
we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1
applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2
substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2
the answer is
the hypotenuse is (3√2)/2
we know that
in the right triangle ABC
cos A=AC/AB
cos A=1/3
so
1/3=AC/AB----->AB=3*AC-----> square----> AB²=9*AC²----> equation 1
applying the Pythagoras Theorem
BC²+AC²=AB²-----> 2²+AC²=AB²---> 4+AC²=AB²----> equation 2
substitute equation 1 in equation 2
4+AC²=9*AC²----> 8*AC²=4----> AC²=1/2----> AC=√2/2
so
AB²=9*AC²----> AB²=9*(√2/2)²----> AB=(3√2)/2
the answer is
the hypotenuse is (3√2)/2
<u>Given</u>:
The coordinates of the points A, B and C are (3,4), (4,3) and (2,1)
The points are rotated 90° about the origin.
We need to determine the coordinates of the point C'.
<u>Coordinates of the point C':</u>
The general rule to rotate the point 90° about the origin is given by
Substituting the coordinates of the point C in the above formula, we get;
Therefore, the coordinates of the point C' is (-1,2)