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Mashcka [7]
3 years ago
8

juan drove 126 miles in 3 hours. If he continued at the same rate, how long would it take to travel 336 miles? ​

Mathematics
2 answers:
MArishka [77]3 years ago
7 0

Answer:

8 hours

Step-by-step explanation:

126 miles - 3 hours

336 miles - x hours

Cross multiply

126x = 336 x 3

126x = 1008

Divide both sides by 126

x = 1008/126

x = 8

ipn [44]3 years ago
3 0

Answer:

8 hours

Step-by-step explanation:

First you divide 126 by 3 to get the Miles Per Hour, you should get 42 Miles Per Hour, then, just divide 336 by 42 to get the numbers of hours he will have to drive, (which is 8)

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A savings account offers 0.8% interest compounded bimonthly. If Bob deposited $300 into this account, how much interest will he
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Step-by-step explanation:

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Prove :
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Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

\displaystyle \frac{1}{\sec\alpha+1}-\frac{\cos\alpha}{\sin^2\alpha}=\frac{\cos\alpha }{\sin^2\alpha }-\frac{1}{\sec\alpha -1}

We can convert sec(α) to 1 / cos(α):

\displaystyle \frac{1}{1/\cos\alpha+1}-\frac{\cos\alpha}{\sin^2\alpha}=\frac{\cos\alpha }{\sin^2\alpha }-\frac{1}{\sec\alpha -1}

Multiply both layers of the first fraction by cos(α):

\displaystyle \frac{\cos\alpha}{1+\cos\alpha}-\frac{\cos\alpha}{\sin^2\alpha}=\frac{\cos\alpha }{\sin^2\alpha }-\frac{1}{\sec\alpha -1}

Create a common denominator. We can multiply the first fraction by (1 - cos(α)):

\displaystyle \frac{\cos\alpha(1-\cos\alpha)}{(1+\cos\alpha)(1-\cos\alpha)}-\frac{\cos\alpha}{\sin^2\alpha}=\frac{\cos\alpha }{\sin^2\alpha }-\frac{1}{\sec\alpha -1}

Simplify:

\displaystyle \frac{\cos\alpha(1-\cos\alpha)}{1-\cos^2\alpha}-\frac{\cos\alpha}{\sin^2\alpha}=\frac{\cos\alpha }{\sin^2\alpha }-\frac{1}{\sec\alpha -1}

From the Pythagorean Identity, we know that cos²(α) + sin²(α) = 1 or equivalently, 1 - cos²(α) = sin²(α). Substitute:

\displaystyle \frac{\cos\alpha(1-\cos\alpha)}{\sin^2\alpha}-\frac{\cos\alpha}{\sin^2\alpha}=\frac{\cos\alpha }{\sin^2\alpha }-\frac{1}{\sec\alpha -1}

Subtract:

\displaystyle \frac{\cos\alpha(1-\cos\alpha)-\cos\alpha}{\sin^2\alpha}=\frac{\cos\alpha}{\sin^2\alpha}-\frac{1}{\sec\alpha-1}

Distribute:

\displaystyle \frac{\cos\alpha-\cos^2\alpha-\cos\alpha}{\sin^2\alpha}=\frac{\cos\alpha}{\sin^2\alpha}-\frac{1}{\sec\alpha-1}

Rewrite:

\displaystyle \frac{(\cos\alpha)-(\cos^2\alpha+\cos\alpha)}{\sin^2\alpha}=\frac{\cos\alpha}{\sin^2\alpha}-\frac{1}{\sec\alpha-1}

Split:

\displaystyle \frac{\cos\alpha}{\sin^2\alpha}-\frac{\cos^2\alpha+\cos\alpha}{\sin^2\alpha}=\frac{\cos\alpha}{\sin^2\alpha}-\frac{1}{\sec\alpha-1}

Factor the second fraction, and substitute sin²(α) for 1 - cos²(α):

\displaystyle \frac{\cos\alpha}{\sin^2\alpha}-\frac{\cos\alpha(\cos\alpha+1)}{1-\cos^2\alpha}=\frac{\cos\alpha}{\sin^2\alpha}-\frac{1}{\sec\alpha-1}

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Cancel:

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