Perimeter is the length around an object
Answer:
Answer is 
Step-by-step explanation:
To find the interval of x. Use our equations to equal each other.



Integrate.
![\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3} =4/3](https://tex.z-dn.net/?f=%5Cfrac%7B-x%5E3%7D%7B3%7D%2Bx%5E2%5C%5C%28%5Cfrac%7B-2%5E3%7D%7B3%7D%2B2%5E2%29-%5B%5Cfrac%7B-0%5E3%7D%7B3%7D%2B0%5E2%5D%5C%5C-%5Cfrac%7B8%7D%7B3%7D%20%2B4-0%5C%5C-%5Cfrac%7B8%7D%7B3%7D%2B%5Cfrac%7B12%7D%7B3%7D%20%20%3D4%2F3)
Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.
Proof Check your interval of x.
Answer:
32
Step-by-step explanation:
f(x)= 3(x-2)² + 5
Let x = -1
f(-1)= 3(-1-2)² + 5
Parentheses first
f(-1) = 3(-3)^2 +5
Exponents
f(-1)= 3*9 + 5
Multiply
f(-1) = 27+5
Add
f(-1) = 32
Answer:
reflections across the x axis and a shift down 3 units
Step-by-step explanation:
y = x^2
The negative sign means it is a reflection across the x axis y = −f(x)
y = -x^2
The subtraction of 3 means we are shifting down 3 units
y = -x^2 -3