Question

ASAP PLZZZ The axis of symmetry for the graph of the function f start bracket x end bracket equals one-quarter x square plus b x plus 10 is x=6. What is the value of b? −12 −3 3

Answer 1

Answer:

$b=-3$

Step-by-step explanation:

The  given function is $f(x)=\frac{1}{4}x^2+bx+10$.

When we compare to $ax^2+bx+=0$, we have

$a=\frac{1}{4}$ and c=10

The equation of the axis of symmetry of a vertical parabola is:

$x=-\frac{b}{2a}$

Also from the question the axis of symmetry is x=6

We substitute the values to get:

$6=-\frac{b}{2*\frac{1}{4}}$

$6=-\frac{b}{\frac{1}{2}}$

$b=-\frac{1}{2}*6$

$b=-3$

Answer 2

Answer:

B

Step-by-step explanation: