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Dennis_Churaev [7]

3 years ago

8

ASAP PLZZZ The axis of symmetry for the graph of the function f start bracket x end bracket equals one-quarter x square plus b x

plus 10 is x=6. What is the value of b? −12 −3 3

2 answers:

Lilit [14]3 years ago

7 0

Answer:

$b=-3$

Step-by-step explanation:

The given function is $f(x)=\frac{1}{4}x^2+bx+10$ .

When we compare to $ax^2+bx+=0$ , we have

$a=\frac{1}{4}$ and c=10

The equation of the axis of symmetry of a vertical parabola is:

$x=-\frac{b}{2a}$

Also from the question the axis of symmetry is x=6

We substitute the values to get:

$6=-\frac{b}{2*\frac{1}{4}}$

$6=-\frac{b}{\frac{1}{2}}$

$b=-\frac{1}{2}*6$

$b=-3$

Margarita [4]3 years ago

7 0

Answer:

B

Step-by-step explanation:

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<em></em> $\%Increase = 118\%$ <em></em>

<em></em>

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