Answer:
its speed is insignificant before the diver's speed change, so the result does not change
Explanation:
In this exercise of conservation of the momentum, the system is formed by the diver and the Earth
initial instant (before jumping)
p₀ = 0
final instant (after jumping)
= m v + M v²
how momentum is conserved
p₀ = p_{f}
0 = m v + M v²
v² = m / M v
since the mass of the Earth is M = 10²⁴ kg
its speed is insignificant before the diver's speed change, so the result does not change
The mass can be calculated by dividing the net force acting on an object by the acceleration of the object. When talking about net force, we use the units kilogram meter per second squared. This is also known as a Newton. The units for acceleration is meters per seconds squared, and the units for mass are kilograms.
Earth distance to the Sun is about 40 times the Moon's distance from earth.
<u>Explanation:</u>
- The Earth's distance from the Sun is about 93 million miles. When it expressed in Km, it is 150 million Km.
- The Moon's distance from Earth is 238,855 miles. When it is 40 times then it will approximately equal to 93 million miles.
- The Sun's distance from Venus is 67.237 million miles. The Sun's distance from mercury is 35.832 million miles.
Answer:
Explanation:
Force on q due to Q
= k Qq / ( a² + d²)
x component
= k Qq / ( a² + d²) x d /√ ( a² + d²)
F = kQq d/ ( a² + d²)³/²
differentiating F with respect to d
dF / Dd = kQq [ d. -3/2 ( a² + d²)⁻⁵/² 2d + ( a² + d²)⁻³/²]=0 for maximum F
- 3d² / ( a² + d²) + 1 = 0
a² + d² = 3 d²
a² = 2d²
d = a / √2
Answer:
Explanation:
As per energy conservation we know that
initial total gravitational potential energy = final spring potential energy
so we have
also we know that maximum acceleration will be 5.3 g
so it is given as
so we have
