A pH scale goes from 0 - 14.
7 is in the middle so it is neutral
Answer:
Frequency of oscillation, f = 4 Hz
time period, T = 0.25 s
Angular frequency, 
Given:
Time taken to make one oscillation, T = 0.25 s
Solution:
Frequency, f of oscillation is given as the reciprocal of time taken for one oscillation and is given by:
f = 
f = 
Frequency of oscillation, f = 4 Hz
The period of oscillation can be defined as the time taken by the suspended mass for completion of one oscillation.
Therefore, time period, T = 0.25 s
Angular frequency of oscillation is given by:



KE = PE
1/2 m • v^2 = mgh
1/2 • v^2 = gh
V^2/2 = gh
2 • (v^2/2) = 2 • (gh)
V^2 = 2gh
V = sq root (2gh).
Answer:
0.0025 sec
Explanation:
Period = 1 / frequency = 1/400 = 0.0025 sec