Answer: Mars has lower gravity and lower magma buoyancy
Explanation: The gravity in mars is low. Low gravity affect the occurrence of volcanic eruptions. The buoyancy of the magma in Mars is lower and the depth of the magma chamber deeper (Buoyancy is the difference in density between the surrounding crust and the magma ascending for eruption). Olympus Mons which is larger and wider than mount Everest was formed as a result of overcoming of the low gravity and buoyancy by the magma to release enormous volume of magma to the surface.
Another reason why the volcanoes on Mars are so large is because the crust on Mars is static unlike Earth.
AnswerShe uses force and air
Explanation:
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A paper clip is a example of a thing that has a mass of one gram.
Answer:
It takes 325 seconds for the signal to reach Earth.
Explanation:
First, you must make a unit change from m/s to km/s in order to make a comparison with the distance of the radio signal sent to Earth. For that, you know that 1 m is 0.001 km. So:

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three. Remember that proportionality is a constant relationship or ratio between different magnitudes.
If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:
a ⇒ b
c ⇒ x

In this case, the rule of three is applied as follows: if by definition of speed, 300,000 km of light are traveled in 1 second, 9.75 * 10⁷ km in how long are they traveled?

time=325 seconds
<em><u>
It takes 325 seconds for the signal to reach Earth.</u></em>
Answer:
(a) E=λ/(2\pi e0 r)
(b) E = 0
Explanation:
(a) We can use the Gaussian's Law to calculate the electric field at any distance r from the axis. By using a cylindrical Gaussian surface we have:

where λ is the total charge per unit length inside the Gaussian surface. In this case we have that the Electric field vector is perpendicular to the r vector. Hence:

(b) outside of the outer cylinder there is no net charge inside the Gaussian surface, because charge of the inner radius cancel out with the inner surface of the cylindrical conductor.
Hence, we have that E is zero.
hope this helps!!