All categories

3 years ago

Convert 15.5 Mm to km

Physics

2 answers:

Galina-37 [17]3 years ago

7 0

Answer:

15.5 Millimeters = 1.55E-5 Kilometers

Explanation:

uysha [10]3 years ago

5 0

Answer:

I guess 15,500

Explanation:

15.5×1000=15,500

You might be interested in

In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system.

BartSMP [9]

Answer:

The value of g in Kepler-12b is $3.85 m/s^{2}$

Explanation:

To determine the value of g at Kepler-12b it is necessary to combine the equation of the weight and the equation for the Universal law of gravity:

$W = m.g$ (1)

Where m is the mass and g is the value of the gravity

$F = G \frac{M.m}{R^{2}}$ (2)

Equation (1) and equation (2) will be equal, since the weight is a force acting on the object as a consequence of gravity:

$m.g = G \frac{M.m}{R^{2}}$ (3)

Then g will be isolated from equation 3:

$g = G \frac{M.m}{m.R^{2}}$

$g = \frac{G.M}{R^{2}}$ (4)

The radius of Jupiter has a value of 69911000 meters, so its diameter can be determined by:

$d = 2R$ (5)

Where d and R are the diameter and radius of Jupiter

$d_{jupiter} = 2(69911000 m)$

$d_{jupiter} = 139822000 m$

Procedure for finding the radius of Kepler-12b:

For the case of Kepler-12b it has a diameter that is 1.7 times that of Jupiter

$d_{Kepler-12b} = 1.7(d_{jupiter})$

$d_{Kepler-12b} = 1.7(139822000 m)$

$d_{Kepler-12b} = 237697400 m$

By means of equation 5 the radius of Kepler-12b can be known:

$R_{Kepler-12b} = \frac{d}{2}$

$R_{Kepler-12b} = \frac{237697400 m}{2}$

$R_{Kepler-12b} = 118848700 m$

Procedure for finding the mass of Kepler-12b:

The mass of Jupiter has a value of $1.898x10^{27}$ kilograms

For the case of Kepler-12b it has a mass that is 0.43 times that of jupiter

$m_{Kepler-12b} = 0.43(m_{jupiter})$

$m_{Kepler-12b} = 0.43(1.898x10^{27} Kg)$

$m_{Kepler-12b} = 8.161x10^{26} Kg$

The value of g in Kepler-12b can be found by replacing its radius and mass in equation 4:

$g = \frac{(6.67x10^{-11} N.m^{2}/Kg^{2})(8.161x10^{26} Kg)}{(118848700 m)^{2}}$

$g = 3.85 m/s^{2}$

Hence, in Kepler-12b the gravity has a value of $3.85 m/s^{2}$

8 0

3 years ago

A 1000-n weight is hanging from a 2.0 m long aluminum rod. A 500-n weight is hanging from a 1.0 m long aluminum rod. The two alu

Hunter-Best [27]

Answer:

Both rod have the same tensile stress

Explanation:

Given information,

The weight first rod, $W_{1}$ = 1000 N

The length of first rod, $l_{1}$ = 2.0 m

The weight second rod, $W_{2}$ = 500 N

The length of second rod, $l_{2$ = 1.0 m

The equation of tensile stress, σ = $\frac{F}{A}$

where

σ = tensile stress (N/ $m^{2}$ or Pa)

F = Force (N)

A = Area (N/ $m^{2}$ or Pa)

σ1 = $\frac{W_{1} }{A_{1} }$ , A = 2πl

= $\frac{1000}{2\pi(2) }$

= $\frac{250}{\pi }$ N/ $m^{2}$

now calculate σ2

σ2 = $\frac{W_{2} }{A_{2} }$

= $\frac{500}{2\pi(1) }$

= $\frac{250}{\pi }$ N/ $m^{2}$

σ1/σ2 = $\frac{250}{\pi }$ / $\frac{250}{\pi }$

σ1/σ2 = 1

σ1 = σ2

Hence, the tensile stress of first and second rod are the same.

5 0

4 years ago

A rotating wheel requires 5 s to rotate 38 revolutions. Its angular velocity at end of time interval 5-s is 79 rad/s. What is th

Lera25 [3.4K]

"Rotating wheel" is meant to indcate that the wheel is already rotating at the start. Denote the initial angular velocity by ω₀. Then the angular displacement θ at time t is

θ = ω₀t + 1/2 αt ²

while the angular velocity ω is

ω = ω₀ + αt

It takes 5 s for the wheel to rotate 38 times, or turn a total of (2π rad/rev) (38 rev) = 76π rad, as well as to reach an angular velocity of 79 rad/s, so that

76π rad = ω₀ (5 s) + 1/2 α (5 s)²

79 rad/s = ω₀ + α (5 s)

Solve the second equation for ω₀ and substitute into the first equation, then solve for α :

ω₀ = 79 rad/s - α (5 s)

==> 76π rad = (79 rad/s - α (5 s)) (5 s) + 1/2 α (5 s)²

==> 76π rad = (79 rad/s) (5 s) - 1/2 α (5 s)²

==> 1/2 α (5 s)² = (79 rad/s) (5 s) - 76π rad

==> α = ((79 rad/s) (5 s) - 76π rad) / (1/2 (5 s)²)

==> α ≈ 12.5 rad/s²

3 0

3 years ago

A golf ball is at rest on the grass when a golfer walks up and applies 10 N of force to it. There is 2 N of friction, resulting

Lera25 [3.4K]

Answer:

The forth one

Explanation:

8N of net force is applied to the golf ball

7 0

3 years ago

Pls answer!! 20 points and will give crown to best answer!!

docker41 [41]

I am 99999.999999999% sure that it is his second law of motion.

Hope this helped! :) Please mark brainliest

5 0

4 years ago