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Oduvanchick [21]
3 years ago
10

Convert 15.5 Mm to km

Physics
2 answers:
Galina-37 [17]3 years ago
7 0

Answer:

15.5 Millimeters = 1.55E-5 Kilometers

Explanation:

uysha [10]3 years ago
5 0

Answer:

I guess 15,500

Explanation:

  • 15.5×1000=15,500
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A wire with a linear mass density of 1.17 g/cm moves at a constant speed on a horizontal surface and the coefficient of kinetic
stira [4]

Answer:

The value is B  =  0.2312 \  T

The direction is into the surface

Explanation:

From the question we are told that

   The mass density is  \mu =\frac{m}{L}  = 1.17 \ g/cm =0.117 kg/m

   The coefficient of kinetic friction is  \mu_k  =  0.250

   The current the wire carries is  I =  1.24 \  A

Generally the magnetic force acting on the wire is mathematically represented as

         F_F   = F_B

Here   F_F is the frictional  force which is mathematically represented as

      F_F =  \mu_k *  m *  g

While F_B  is the magnetic force which is mathematically represented as

       F_B  = BILsin(\theta )

Here \theta =90^o is the angle between the direction of the force and that of the current

So

      F_B  = BIL

So

      BIL  =  \mu_k * m * g

=>   B  =  \mu_k *  \frac{m}{L} * [\frac{g}{I} ]

=>   B  =  0.25 *  0.117  * [\frac{9.8}{1.24} ]

=>   B  =  0.2312 \  T

Apply the right hand curling rule , the thumb pointing towards that direction of the current we see that the direction of the magnetic field is into the surface as shown on the first uploaded image

8 0
3 years ago
Một oto đang chạy với vận tốc là 10m/s thì tăng tốc và chuyển động nhanh dần đều sau 20s thì đạt vận tốc 14m/s
Tasya [4]

a) gia tốc = vf-vi / t

a = 14-10 / 20

a = 0,2ms⁻²

b) dưới dạng a = Δv / t

v = lúc

v = 0,2 × 40

v = 8ms⁻¹

như v = d / t

do đó d = vt

d = 8 × 40

d = 320m

hãy đánh dấu là trí óc nhất

4 0
3 years ago
Which of the following would most likely be an example of a mass-transit disaster?
Aleonysh [2.5K]

Answer:

i think it is c if not im sorry if im wrong

Explanation:

7 0
3 years ago
An athlete can twirl a baton so that it reaches an angular velocity of 12 rad/s from rest in 0.5 s. If the length of a uniform b
NikAS [45]

Answer:

The torque needed is 46.08 Nm

Explanation:

Given;

angular velocity, ω = 12 rad/s

time of motion, t = 0.5 s

length of the baton, r = 0.8 m

mass of the baton, 0.5 kg

The torque needed to  reach the angular velocity is given by;

τ = F x r

where;

F is the centripetal force of the baton

r is the length of the baton = radius of the circular motion of the baton

F_c =ma_c= \frac{mv^2}{r} = m\omega^2 r

Torque is given by;

\tau = F_c *r\\\\\tau = m \omega^2 r *r\\\\\tau = m \omega^2 r^2 \\\\\tau = (0.5)(12)^2(0.8)^2\\\\\tau = 46.08 \ N m

Therefore, the torque needed is 46.08 Nm

6 0
3 years ago
An object is acted upon by the forces F1equalsleft angle12​,7​,2right angle and F2equalsleft angle0​,4​,8right angle. Find the f
Umnica [9.8K]

Answer:

F_3=(-12,-11,-10)

Explanation:

It is given that,

Force, F_1=(12,7,2)

Force, F_2=(0,4,8)

We need to find the force F₃ that must act on the object so that the sum of the forces is zero. Let F_3=(x,y,z)

According to question, F_1+F_2+F_3=0

(12,7,2)+(0,4,8)+(x,y,z)=0

(12+x)+(11+y)+(10+z)=0

Since, 12 + x = 0, 11 + y = 0 and 10 + z = 0

The third force is equal to,

F_3=(-12,-11,-10)

Hence, this is the required solution.

4 0
3 years ago
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