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3 years ago

Convert 15.5 Mm to km

Physics

2 answers:

Galina-37 [17]3 years ago

7 0

Answer:

15.5 Millimeters = 1.55E-5 Kilometers

Explanation:

uysha [10]3 years ago

5 0

Answer:

I guess 15,500

Explanation:

15.5×1000=15,500

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A wire with a linear mass density of 1.17 g/cm moves at a constant speed on a horizontal surface and the coefficient of kinetic

stira [4]

Answer:

The value is $B = 0.2312 \ T$

The direction is into the surface

Explanation:

From the question we are told that

The mass density is $\mu =\frac{m}{L} = 1.17 \ g/cm =0.117 kg/m$

The coefficient of kinetic friction is $\mu_k = 0.250$

The current the wire carries is $I = 1.24 \ A$

Generally the magnetic force acting on the wire is mathematically represented as

$F_F = F_B$

Here $F_F$ is the frictional force which is mathematically represented as

$F_F = \mu_k * m * g$

While $F_B$ is the magnetic force which is mathematically represented as

$F_B = BILsin(\theta )$

Here $\theta =90^o$ is the angle between the direction of the force and that of the current

$F_B = BIL$

$BIL = \mu_k * m * g$

=> $B = \mu_k * \frac{m}{L} * [\frac{g}{I} ]$

=> $B = 0.25 * 0.117 * [\frac{9.8}{1.24} ]$

=> $B = 0.2312 \ T$

Apply the right hand curling rule , the thumb pointing towards that direction of the current we see that the direction of the magnetic field is into the surface as shown on the first uploaded image

8 0

3 years ago

Một oto đang chạy với vận tốc là 10m/s thì tăng tốc và chuyển động nhanh dần đều sau 20s thì đạt vận tốc 14m/s

Tasya [4]

a) gia tốc = vf-vi / t

a = 14-10 / 20

a = 0,2ms⁻²

b) dưới dạng a = Δv / t

v = lúc

v = 0,2 × 40

v = 8ms⁻¹

như v = d / t

do đó d = vt

d = 8 × 40

d = 320m

hãy đánh dấu là trí óc nhất

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3 years ago

Which of the following would most likely be an example of a mass-transit disaster?

Aleonysh [2.5K]

Answer:

i think it is c if not im sorry if im wrong

Explanation:

7 0

3 years ago

An athlete can twirl a baton so that it reaches an angular velocity of 12 rad/s from rest in 0.5 s. If the length of a uniform b

NikAS [45]

Answer:

The torque needed is 46.08 Nm

Explanation:

Given;

angular velocity, ω = 12 rad/s

time of motion, t = 0.5 s

length of the baton, r = 0.8 m

mass of the baton, 0.5 kg

The torque needed to reach the angular velocity is given by;

τ = F x r

where;

F is the centripetal force of the baton

r is the length of the baton = radius of the circular motion of the baton

$F_c =ma_c= \frac{mv^2}{r} = m\omega^2 r$

Torque is given by;

$\tau = F_c *r\\\\\tau = m \omega^2 r *r\\\\\tau = m \omega^2 r^2 \\\\\tau = (0.5)(12)^2(0.8)^2\\\\\tau = 46.08 \ N m$

Therefore, the torque needed is 46.08 Nm

6 0

3 years ago

An object is acted upon by the forces F1equalsleft angle12,7,2right angle and F2equalsleft angle0,4,8right angle. Find the f

Umnica [9.8K]

Answer:

$F_3=(-12,-11,-10)$

Explanation:

It is given that,

Force, $F_1=(12,7,2)$

Force, $F_2=(0,4,8)$

We need to find the force F₃ that must act on the object so that the sum of the forces is zero. Let $F_3=(x,y,z)$

According to question, $F_1+F_2+F_3=0$

$(12,7,2)+(0,4,8)+(x,y,z)=0$

$(12+x)+(11+y)+(10+z)=0$

Since, 12 + x = 0, 11 + y = 0 and 10 + z = 0

The third force is equal to,

$F_3=(-12,-11,-10)$

Hence, this is the required solution.

4 0

3 years ago