We are given 3 equations. Using these equations we can find f(h(2)).
h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
h(2)=9
f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
f(9)=9^2-7
f(9)=81-7
f(9)=74
so f(h(2))=74
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Answer
Perimeter of rectangle, P = 2L + 2W
P = 36ft
Width, W
Length, L = W + 2ft
Perimeter of rectangle, P = 2L + 2W
Given; P = 36ft
36ft = 2W + 2(W + 2ft)
36ft = 2W + 2W + 4ft
32ft = 4W
8ft = W
L = W + 2ft
L = 8ft + 2ft
L = 10ft
