Answer:
7.3% of the bearings produced will not be acceptable
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.
So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.
Larger than 0.504
1 subtracted by the pvalue of Z when X = 0.504.
has a pvalue of 0.9938
1 - 0.9938= 0.0062
Smaller than 0.496
pvalue of Z when X = -1.5
has a pvalue of 0.0668
0.0668 + 0.0062 = 0.073
7.3% of the bearings produced will not be acceptable
From the graph: there are 200 students overall. For the next 100, we can divide each number by 2 to find an estimate for how many with participate in MATH tutoring. 40 divided by 2 =20 students participating in MATH tutoring.
Part B- There are currently 55 students out of 200 in SCIENCE tutoring. We add 55 more for 400 = 110, add 55 more for 600=165, and then add half of 55 (27.5 or 28 because you CANNOT have half a student) for 700 students total. 55+55+55+28=193 students.
Step-by-step explanation:
9:
A=V/t
A=8.0m/s•1/2.0s
A=8.0m/2.0s²
A=4.0m/s²
10:
V=A•time
V=4.0m/s²•2.3s
V=9.2m/s
11:
V=A•t
24.0=5.6t
4.3s=t
In this question, we have to write the set of points from -6 to 3 but excluding -2 and 3 as a union of intervals .
For union, we use U.
For the points that we have to exclude , we put parenthesis on there side that is ().
Therefore the required interval form is
As we see that () are used with -2 and 3 . And that's the required interval form .
Answer:
-3
Step-by-step explanation:
Step 1: Solve (-2+(-1))^2/3 3
1. -2+(-1) = -3
2. (-3)^2 = 9
3. 9/3 = 3
Step 2: Solve (-4)^2-17 -1
1. 3/-1
Step 3: Simplify 3/-1 = -3. I hope this helped and please don't hesitate to reach out with more questions!
