The missing side length is c = 25 units.
Step-by-step explanation:
Step 1:
The given triangle has a 24 unit long adjacent side and a 7 unit long opposite side. 
As we have two sides of the triangle, we can solve for the length of the other side by using Pythagoras' theorem. 
The length of the hypotenuse is given as c units. 
Step 2:
According to Pythagoras theorem,


So the missing length, c of the given triangle is 25 units.
 
        
             
        
        
        
The fourth class ends at 12:30 pm
<em><u>Solution:</u></em>
Given that Harold has 4 classes each morning
Each class is 1 hour long, and there are 10 minutes between classes
The first class is at 8 A.M
<em><u>To find: Time at which fourth class ends</u></em>
Since each is 1 hour long and 10 minutes gap between classes
First class = 8 A.M to 9 A.M
Second class = 9:10 A.M to 10 : 10 AM
Third class = 10 : 20 AM to 11 : 20 AM
Fourth class = 11 : 30 AM to 12 : 30 PM
Thus the fourth class ends at 12:30 pm
 
        
             
        
        
        
Answer:
A
Step-by-step explanation:
The Y-intercept is -3. 
The gradient is -3/4 since it goes down 3 every 4 tiles.
 
        
                    
             
        
        
        
What we know:
we know that there are <u>75</u> chicks in the hen house, we also know that in all there are 108 chicks
What we need to find:
we need to find out how many chicks were outside
Answer equation:
108 - 75 = 33
 
        
             
        
        
        
QUESTION 1
We want to solve,

We factor the denominator of the fraction on the right hand side to get,

This implies 


We multiply through by LCM of 


We expand to get,

We group like terms and equate everything to zero,

We split the middle term,

We factor to get,





But 

is not in the domain of the given equation.
It is an extraneous solution.

is the only solution.
QUESTION 2

We add x to both sides,

We square both sides,

We expand to get,

This implies,

We solve this quadratic equation by factorization,





But 

is an extraneous solution 
