Answer:






Step-by-step explanation:
Given

See attachment for proper table
Required
Complete the table
Experimental probability is calculated as:

We use the above formula when the frequency is known.
For result of roll 2, 4 and 6
The frequencies are 13, 29 and 6, respectively
So, we have:



When the frequency is to be calculated, we use:


For result of roll 3 and 5
The probabilities are 0.144 and 0.296, respectively
So, we have:


For roll of 1 where the frequency and the probability are not known, we use:

So:
Frequency(1) added to others must equal 125
This gives:


Collect like terms


The probability is then calculated as:


So, the complete table is:






Answer:
(3,3) ( 1,2) (3,1) (-2,-2) (-2 3)
Step-by-step explanation:
have a good day
E=16 pls brainliest me have a good day/night
We breakdown the components of the distances.
(1) 90 miles west.
x - component = -90 miles
y - component = 0 miles
(2) 80 miles, northwest (120°)
x - component = (80 miles)*(sin 30°) = 40 miles (negative)
y - component =(80 miles)*(cos 30°) = 69.282 miles (positive)
Solve for the distance,
√(-90 - - 40)² + (69.282 miles)² = <em>147.31 miles</em>
<span>associative property of addition
(a+b) + c = a + (b +c)
hope that helps.....</span>