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Sergeeva-Olga [200]

4 years ago

14

Please round to the nearest tenth if possible.

1 answer:

Butoxors [25]4 years ago

8 0

$\bf \cfrac{64~\underline{mi}}{\underline{hr}}\cdot \cfrac{\underline{hr}}{60~sec}\cdot \cfrac{5200~ft}{\underline{mi}}\implies \cfrac{64\cdot 5200~ft}{60~sec}\implies \cfrac{16640~ft}{3~sec}
\\\\\\
\approx 5546.67\frac{ft}{sec}\\\\
-------------------------------\\\\
\cfrac{6000~\underline{lbs}}{\underline{day}}\cdot \cfrac{ton}{2000~\underline{lbs}}\cdot \cfrac{7~\underline{day}}{week}\implies \cfrac{6000\cdot 7~ton}{2000~week}\implies 21.00\frac{ton}{week}$

$\bf -------------------------------\\\\
\cfrac{2~\underline{lbs}}{\underline{week}}\cdot \cfrac{16~oz}{\underline{lbs}}\cdot \cfrac{\underline{week}}{7~day}\implies \cfrac{2\cdot 16~oz}{7~day}\implies \cfrac{32~oz}{7~day}\approx 4.57\frac{oz}{day}$

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Find the length of diagonal HJ. Round to the nearest hundredth.

Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ , where

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ $x_{1}=-4$ and $x_{2}=5$

∴ $y_{1}=3$ and $y_{2}=-3$

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = $\sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}$

∴ HJ = $\sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665$

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

7 0

3 years ago

Given tanθ = 8, find csc(θ)

In-s [12.5K]

Cosecθ=sq.rt of 65/8. hope it will help you

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3 years ago

Read 2 more answers

11. How many different ways can the 16 numbered pool balls be placed in a line on the pool table?

nikklg [1K]

Answer:

The number of ways are 16! or 20,922,789,888,000.

Step-by-step explanation:

Consider the provided information.

We need to determine the number of different ways 16 numbered pool balls be placed in a line on the pool table.

For the first place we have 16 balls.

For the second place we have 15 balls left.

Similarly for the third place we have 14 balls as two balls are already arranged and so on.

Or we can say that this is the permutation of 16 things taking 16 at a time.

Thus the number of ways are: $16!$ or $^{16}P_{16}$

$16!=16\times15\times14\times13......\times2\times1=20,922,789,888,000$

Hence, the number of ways are 16! or 20,922,789,888,000.

7 0

3 years ago

an angle measures 27.4 more than the measure of its complementary angle what is the measure of each angle

Arisa [49]

Hello!

<h2>31.3° and 58.7°</h2><h2></h2>

To solve, we can set up an algebraic expression.

Complementary angles add up to 90°, and in this instance, one angle is 27.4° more than the other. Therefore:

∠1 = x

∠2 = x + 27.4°

∠1 + ∠2 = 90°

x + (x + 27.4°) = 90°

Combine like terms:

2x + 27.4° = 90°

Subtract 27.4 from both sides:

2x = 62.6°

Divide both sides by 2:

x = 31.3°

Therefore, one of the angles is 31.3°. Solve for the measure of the other angle:

(31.3°) + 27.4° = 58.7°

3 0

3 years ago

Given side lengths of 15cm and 20cm, how many triangles can you build?

Dmitry_Shevchenko [17]

20cm + 15cm= 35 triangles

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3 years ago