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lapo4ka [179]
3 years ago
12

The volume of a cone is 3πx3 cubic units and its height is x units.

Mathematics
1 answer:
WINSTONCH [101]3 years ago
5 0
I think the answer is c or d if im wrong sorry hope this helped tho :p
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PLEASE HELP ME ITS ALGEBRA THANK YOUUUU
mina [271]

Answer:

2924

Step-by-step explanation:

2752 ÷ 16 = 172 ← number of points per coin

After collecting 17 points he will have collected

2752 + 172 = 2924 points in total

5 0
3 years ago
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A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. if th
Oxana [17]
1 revolution of a circle = circumference of that circle.

<span>1 revolution of a circle with the diameter of 28 inches = </span><span><span>πd=28π</span><span>πd=28π</span></span><span> inches. Hence, x revolutions per second = </span><span><span>28πx</span><span>28πx</span></span><span> inches per second = </span><span><span>60∗28πx</span><span>60∗28πx</span></span><span> inches </span>per minute.

<span>Given that </span><span><span>60∗28πx=35πn</span><span>60∗28πx=35πn</span></span><span> --> </span><span><span>n=<span><span>60∗28πx</span><span>35π</span></span>=48x</span><span>n=<span><span>60∗28πx</span><span>35π</span></span>=48x</span></span><span>.</span>
7 0
3 years ago
SOS bro i need help!!!!
Masteriza [31]

Answer:

It’s the first one

Step-by-step explanation:

I

3 0
3 years ago
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If 4x=0 then x is what number
IRINA_888 [86]

Answer:

X=0

Step-by-step explanation:

4x=0

divide both sides by 4

x=0/4

x=0

5 0
3 years ago
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A race car can complete 8 laps in 1/3 hour. At this rate, how many hours will it take the race car to complete 1 lap? 1/240 1/24
Marrrta [24]

Answer:

<h3>1/24</h3>

Step-by-step explanation:

The race car is doing 8 laps in 1/3 hour, in one hour the car is doing:

8laps * (1/3) hour) = 8*3 laps / 1hour = 24 laps/hour.

Now, to complete one lap, the car will it take:

1 lap * (1 hour / 24 laps) = 1/24 hours the race car requires to complete 1 lap. Right answer is:

<h3>1/24</h3>
8 0
3 years ago
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