The equation of a circle exists:
, where (h, k) be the center.
The center of the circle exists at (16, 30).
<h3>What is the equation of a circle?</h3>
Let, the equation of a circle exists:
, where (h, k) be the center.
We rewrite the equation and set them equal :
We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.
-2hx = -32x
h = -32/-2
⇒ h = 16.
-2ky = -60y
k = -60/-2
⇒ k = 30.
The center of the circle exists at (16, 30).
To learn more about center of the circle refer to:
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Answer:
16 and 18
Step-by-step explanation:
Answer:
An identity matrix, is a matrix that have '1' in the main diagonal. All of the other terms are '0'. When you multiply any matrix by the identity matrix, the result is the same matrix that you multiplied.
Example:
![\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%260%260%5C%5C0%261%260%5C%5C0%260%261%5Cend%7Barray%7D%5Cright%5D)
In the set of the real number is the same that the application of identity property.
Every number multiplied by 1 es the same number.
Step-by-step explanation:
It wants it to be in slope-intercept form.
y=mx+b
We have to first find the slope and plug it into point-slope form.
y-y1=m(x-x1)
Find the slope of the second line. (I did this one first on accident)
Rise/run= 3/1= 3 The slope is 3. Plug that in along with the point (0,3)
y-3=3(x-0)
y-3=3x
Add 3 to the other side.
y= 3x +3 <- <em>for the second line</em><em>
</em>
Now, the second.
rise/run= 1/2= .5 Use point (6,0)
y-0=.5(x-6)
y= .5x-3
y=.5x-3 <- for the first line
I hope this helps!
~kaiker
Answer:
Determination of HYP,OPP,ADJ with respect to x.
<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>right</u><u> </u><u>angle</u><u>:</u><u>Hypotenuse</u><u>:</u><u> </u><u>AC</u>
<u>Opposite</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>given</u><u> </u><u>angle</u><u>:</u><u> </u><u>Opp</u><u>:</u><u>BC</u>
<u>remaining</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u>:</u><u> </u><u>Adjacent</u><u>:</u><u>AB</u><u>.</u>
