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Tom [10]
2 years ago
7

What is 0.025 as a fraction

Mathematics
1 answer:
sertanlavr [38]2 years ago
5 0
0.025 as a fraction would be 1 / 40
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Question 5, x could be either 6 or -1.

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if 20 students ride on your bus and two fifth of them pack there lunches how many of them didnt pack there lunch
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12.

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3 years ago
What kind of sequence is the pattern 15, 17, 20, 24, 29,
VikaD [51]

\implies {\blue {\boxed {\boxed {\purple {\sf { \: 15, 17, 20, 24, 29,35, 42}}}}}}

\sf \bf {\boxed {\mathbb {Step-by-step\:explanation:}}}

\: 15, 17, 20, 24, 29,35, 42

➺ \: 15 + 2 = 17

➺\: 17 + 3 = 20

➺\: 20 + 4 = 24

➺\: 24 + 5 = 29

➺\: 29 + 6 = 35

➺\: 35 + 7 = 42

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}

7 0
2 years ago
The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
zloy xaker [14]

Answer:

103=  p small

plarge = 123

Step-by-step explanation:

We know that the the ratio of the areas is the scale factor squared/

Larger triangle over smaller triangle

72

----- = scale factor ^2

50

simplify by dividing by 2 on top and bottom

36

----- = scale factor ^2

25

Take the square root of each side

sqrt(36)

-------------- = sqrt(scale factor ^2)

sqrt(25)

6

-------------- = scale factor

5

The ratio of the perimeters is the scale factor

p large             6

-------------- = ----------------

 p small                5

Using cross products

6 p large = 5 p small

We know the sum is 226

p large + p small = 226

p large = 226 - p small

We have 2 equation and 2 unknowns

6 p large = 5 p small

Substitute for p large

6 (226 - p small) = 5 p small

1356 - 6 p small = 5 p small

Add 6 p small to each side

1356 = 11 p small

divide by 11

1356/11 =  p small

P large = 226-1356/11

p large = 2486/11-1356/11

plarge = 1130/11

The solution requires whole number answers so

1356/11 =  p small

123.27 which rounds to 123

plarge = 1130/11

plarge = 102.7272 = 103

6 0
2 years ago
PLEASE ANSWERR CORRECTLY!!!!!!!!
kogti [31]

Answer:

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