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ratelena [41]
3 years ago
12

Jack owns a 10% interest in a partnership (not real estate) in which his at-risk amount is $42,000 at the beginning of the year.

During the year, the partnership borrows $80,000 on a nonrecourse note and incurs a loss of $60,000 from operations. Jack's at-risk amount at the end of the year is $44,000.
Mathematics
1 answer:
Lynna [10]3 years ago
5 0

Answer:  The correct answer is :  False

Step-by-step explanation:  Jack's year-end risk amount is:

10% loss :  $ 60,000 x 10% = $ 6,000

$ 42,000 - $ 6,000 = $ 36,000, this is the value of Jack's year-end risk amount

The amount a taxpayer has at risk is increased by the taxpayer's share of additional recourse debt and decreased by the share of losses from the activity. The at-risk amount is not affected by nonrecourse debt.

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The sum of five times a number, and 1, is equal to four times the number
larisa86 [58]

Answer:

5x + 1 = 4x

You can really put any letter for "a number":

5n + 1 = 4n

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2 years ago
A. Figure A
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Figure b

Step-by-step explanation:

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Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?
azamat

Answer:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}

From the question, the center of the circle is located at (-6,2) and the radius is

r =  \sqrt{10}

We substitute the center and radius to get:

{(x -  - 6)}^{2}  +  {(y - 2)}^{2}  =  {( \sqrt{10} })^{2}

Simplify to obtain:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

7 0
2 years ago
Pleaseeee helpppppppppp
o-na [289]

Answer:

25 ft^2

Step-by-step explanation:

In direct variation, if y varies directly with x, then the equation has the form

y = kx,

where k is the constant of proportionality. y is proportional to x.

Let's call the area y and the distance x.

Here, the area varies with the square of the distance, so the equation has the form

y = kx^2

Here, y is proportional to the square of x.

We can find the value of k by using the given information.

y = kx^2

When x = 20 ft, y = 16 ft^2.

16 = k(20^2)

k = 16/400

k = 1/25

The equation of the relation is:

y = (1/25)x^2

Now we use the equation we found to answer the question.

What is y (the area) when x (the distance) is 25 ft?

y = (1/25)x^2

y = (1/25)(25^2)

y = 25

Answer: 25 ft^2

5 0
2 years ago
Một lô hàng chứa rất nhiều sản phẩm, trong đó tỷ lệ sản phẩm loại tốt là 70%. chọn ngẫu nhiên từ lô hàng ra 5 sản phẩm. gọi X là
den301095 [7]

trả lời : lâp bảng

X=0 thì xác suất lấy ra được sản phẩm tốt là 5*30%=1,5%

X =1 thì xác suất lấy ra được là 1* 70%*4*30%=0,84%

X=2 thì xác suất lấy ra được sản phẩm tốt là 2*70%*3*30%=1,26%

X=3 thì xác suất lấy ra được sản phẩm tốt là 3*70%*2*30%=1,26%

X=4 thì xác suất lấy ra được sản phẩm tốt là 4*70%*1*30%=0,84%

X=5 thì xác suất lấy ra được sản phẩm tốt là 5*70%=3,5%

X 0 1 2 3 4 5

P 1,5 0,84 1,26 1,26 0,84 3,5

b,

E(x)= 1,5*0+ 0,84*1+1,26*2+1,26*3+0,84*4+3,5*5=28

E(x^2)=1,5*0^2+0,84*1^2+1,26*2^2+1,26*3^2+0,84*4^2+3,5*5^2=118,16

===> V(x)= (E(x))^2-E(x^2)=28^2-118,16=665,84

8 0
2 years ago
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