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ratelena [41]
3 years ago
12

Jack owns a 10% interest in a partnership (not real estate) in which his at-risk amount is $42,000 at the beginning of the year.

During the year, the partnership borrows $80,000 on a nonrecourse note and incurs a loss of $60,000 from operations. Jack's at-risk amount at the end of the year is $44,000.
Mathematics
1 answer:
Lynna [10]3 years ago
5 0

Answer:  The correct answer is :  False

Step-by-step explanation:  Jack's year-end risk amount is:

10% loss :  $ 60,000 x 10% = $ 6,000

$ 42,000 - $ 6,000 = $ 36,000, this is the value of Jack's year-end risk amount

The amount a taxpayer has at risk is increased by the taxpayer's share of additional recourse debt and decreased by the share of losses from the activity. The at-risk amount is not affected by nonrecourse debt.

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Nat2105 [25]

28=12+x

28 represents how tall he will get, 12 represents how tall he is in inches, and x is how much he still has left to grow! Hope it helps!

4 0
3 years ago
A N S W E R Q U I C K P L E A S E
chubhunter [2.5K]

Answer:

1. A

2. D

3. D

Step-by-step explanation:

The standard form of a parabola is

y=\frac{1}{4p}(x-h)^2+k            ..... (1)

Where, (h,k) is vertex, (h,k+p) is focus and y=k-p is directrix.

1. The directrix of a parabola is y=−8 . The focus of the parabola is (−2,−6) .

k-p=-8                   ...(a)

(h,k+p)=(-2,-6)

k+p=-6            .... (b)

h=-2

On solving (a) and (b),  we get k=-7 and p=1.

Put h=-2, k=-7 and p=1 in equation (1).

y=\frac{1}{4(1)}(x-(-2))^2+(-7)

y=\frac{1}{4}(x+2)^2-7

Therefore option A is correct.

2 The directrix of a parabola is the line y=5 . The focus of the parabola is (2,1) .

k-p=5                   ...(c)

(h,k+p)=(2,1)

k+p=1            .... (d)

h=2

On solving (c) and (d),  we get k=3 and p=-2.

Put h=2, k=3 and p=-2 in equation (1).

y=\frac{1}{4(-2)}(x-(2))^2+(3)

y=-\frac{1}{8}(x-2)^2+3

Therefore option D is correct.

3. The focus of a parabola is (0,−2) . The directrix of the parabola is the line y=−3 .

k-p=-3                   ...(e)

(h,k+p)=(0,-2)

k+p=-2            .... (f)

h=0

On solving (e) and (f),  we get k=-2.5 and p=0.5.

Put h=0, k=-2.5 and p=0.5 in equation (1).

y=\frac{1}{4(0.5)}(x-(0))^2+(-2.5)

y=\frac{1}{2}(x)^2-2.5

y=\frac{1}{2}(x)^2-\frac{5}{2}

Therefore option D is correct.

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Use the quadratic formula to solve the equation.
allochka39001 [22]
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which of the following is a point slope equation of a line with the point (-6,2) and a slope of 1/2?
wariber [46]

Answer:

y - 2 = 1/2(x + 6)

General Formulas and Concepts:

<u>Algebra I</u>

Point-Slope Form: y - y₁ = m(x - x₁)

  • x₁ - x coordinate
  • y₁ - y coordinate
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Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point (-6, 2)

Slope <em>m</em> = 1/2

<u>Step 2: Find</u>

  1. Substitute in variables [Point-Slope Form]:                                                     y - 2 = 1/2(x - -6)
  2. Simplify:                                                                                                             y - 2 = 1/2(x + 6)
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3 years ago
I need to know the answers to these problems
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5. c = 9
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