What is x given triangleABC ~triangleDBE?
1 answer:
x = 37.5 (or)
Solution:
Given .
Let us take BE = x and BC = 25 + x.
To determine the value of x:
If two triangles are similar then the corresponding angles are congruent and the corresponding sides are in proportion.
Do cross multiplication, we get
Subtract 30x from both sides of the equation.
Divide by 20 on both sides of the equation, we get
x = 37.5 (or)
Hence the value of x is 37.5 or .
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Answer:
the parabola can be written as:
f(x) = y = a*x^2 + b*x + c
first step.
find the vertex at:
x = -b/2a
the vertex will be the point (-b/2a, f(-b/2a))
now, if a is positive, then the arms of the parabola go up, if a is negative, the arms of the parabola go down.
The next step is to see if we have real roots by using the Bhaskara's equation:
Now, draw the vertex, after that draw the values of the roots in the x-axis, and now conect the points with the general draw of the parabola.
If you do not have any real roots, you can feed into the parabola some different values of x around the vertex
for example at:
x = (-b/2a) + 1 and x = (-b/2a) - 1
those two values should give the same value of y, and now you can connect the vertex with those two points.
If you want a more exact drawing, you can add more points (like x = (-b/2a) + 3 and x = (-b/2a) - 3) and connect them, as more points you add, the best sketch you will have.
Hello There!
50*50 is 2,500
