F(x) is continuous for all x.
Pick a point and show that f(x) is either negative or positive. Pick another point and show that f(x) is negative, if positive, or positive, if negative.
At x = 30, f(30) - 1000 = 900 + 10sin(30) - 1000 ≤ 0
Now, show at another point f(x) - 1000 is positive, and hence, there would be root between 30 and such point.
Let's pick 40.
At x = 40, f(40) - 1000 = 1600 + 10sin(40) - 1000 ≥ 0
Since f(x) - 1000 is continuous, there lies a root between 30 and 40, and hence, 30 ≤ c ≤ 40
Answer:
(3, -3)
Step-by-step explanation:
Use the midpoint formula.
x = (x₁ + x₂) / 2
-1.5 = (-6 + x) / 2
-3 = -6 + x
x = 3
y = (y₁ + y₂) / 2
1 = (5 + y) / 2
2 = 5 + y
y = -3
The other endpoint is (3, -3).
Graph: desmos.com/calculator/aze920ns2h
Answer:
15 x 10^-1
Step-by-step explanation:
36÷24=1.5
In this case I'm considering 15 as the base of my standard form.
To make 15 a 1.5, you'll have to move from right to left one unit and on the number line moving from the right to left gives you a negative number of units moved
The answer is -8/15 because you need to cancel out the variables first
