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nekit [7.7K]
3 years ago
5

Find the midpoint (-1,3) and (5,-4)

Mathematics
2 answers:
Dmitrij [34]3 years ago
4 0

Answer:

(2,-0.5)

Step-by-step explanation:

Anna11 [10]3 years ago
4 0

Answer: (2,-0.5)

Step-by-step explanation:

You need to find the difference between the x's and the y's, then divide by 2.

Step 1: Find the difference between the x's

5 + -1 = 4

Step 2: Find the difference between the y's

-4 + 3 = -1

Step 3: Divide both the results by 2

4/2 = 2

-1/2 = -0.5

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Valentin [98]
So you want to plug in the height for h and solve for t

36 = -16t^2+14t+36
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Hope this helped!
6 0
3 years ago
R(x)=2√x s(x)=√x (r/s)(3)
anygoal [31]
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5 0
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Robert needs to cut four shelves from a board that is 2.5 meters long. The second shelf is 18 cm longer than twice the length of
g100num [7]
STEP 1:
convert meters to centimeters
100 cm= 1 meter

= 100 cm/m * 2.5 m
= 250 cm


STEP 2:
x= length of first shelf
2x+18= length of second shelf
x-12= length of third shelf
x+4= length of fourth shelf

since the whole board has to be used, add lengths of all shelves and set it equal to the whole length of the board (250 cm).

x + (2x+18) + (x-12) + (x+4)= 250 cm
combine like terms
5x + 10= 250
subtract both sides by 10
5x= 240
divide both sides by 5
x= 48


STEP 3:
find length of second shelf
= 2x + 18
= 2(48) + 18
= 114 cm


CHECK:
x + (2x+18) + (x-12) + (x+4)= 250
48 + (2(48)+18) + (48-12) + (48+4)= 250
48 + (96+18) + 36 + 52= 250
48 + 114 + 36 + 52= 250
250= 250


ANSWER: Shelf two is 114 cm.

Hope this helps! :)
8 0
3 years ago
Find the value of X ​
Aloiza [94]
The value of x would be 7
7 0
3 years ago
which of the following shows the graphical representation of the solution for the one-variable linear equation 2x-1=3​
Andrej [43]

For this case we have the following equation:

2x-1 = 3

If we add 1 to both sides of the equation we have:

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Dividing between 2 on both sides of the equation we have:

x = \frac {4} {2}\\x = 2

The graph of the solution is shown in the attached figure.

Answer:

See attached image

6 0
3 years ago
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