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Damm [24]
2 years ago
7

TRUE

Mathematics
1 answer:
Kipish [7]2 years ago
5 0

run me my points .

Step-by-step explanation:

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Use the graph to answer the question.
dmitriy555 [2]

Answer:

B.

Step-by-step explanation:

hope it helps :)

3 0
3 years ago
For sin2x+cosx=0, use a double-angle or half-angle formula to simplify the equation and then find all solutions of the equation
Archy [21]

Answer:

Step-by-step explanation:

Given is a trignometric equation in x, as

sin2x+cosx=0

TO make it in one trig ratio, we can replace sin2x as 2sinx cosx

WE get now

2sinxcosx+cosx=0\\

cosx(2sinx+1)=0\\cosx=0, sinx =-0.5\\

Principal solution is x=\frac{\pi}{2} , \frac{-\pi}{6}

x = ±π/2 + 2kπ, where k is any integer or

x=±pi/6 +k pi, where k is any integer.

General solution is

4 0
3 years ago
Please answer this question correctly for 24 points and brainliest!!
amm1812

Answer:

  $110

Step-by-step explanation:

Let a, b, and c represent the earnings of Alan, Bob, and Charles. The problem statement tells us ...

  a + b + c = 480 . . . . . . the combined total of their earnings

  -a + b = 40 . . . . . . . . . . Bob earned 40 more than Alan

  2a - c = 0 . . . . . . . . . . . Charles earned twice as much as Alan

Adding the first and third equations, we get ...

  (a + b + c) + (2a - c) = (480) + (0)

  3a + b = 480

Subtracting the second equation gives ...

  (3a +b) - (-a +b) = (480) -(40)

  4a = 440 . . . . . . . . simplify

  a = 110 . . . . . . . . . . divide by the coefficient of a

Alan earned $110.

_____

<em>Check</em>

Bob earned $40 more, so $150. Charles earned twice as much, so $220.

The total is then $110 +150 +220 = $480 . . . . as required

8 0
3 years ago
Given a minimum usual value of 135.8 and a maximum usual value of 155.9, determine which (1 point) of the following values would
maxonik [38]

Answer:  b. 134

Step-by-step explanation:

Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.

Let x denotes a usual value.

i.e.  135.8< x < 155.9

Therefore , the interval for the usual values is [135.8, 155.9] .

If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.

Let's check all options

a. 137  ,

since  135.8< 137 < 155.9

So , it is usual.

b. 134

since 134<135.8 (Minimum value)

So , it is unusual.

c. 146  

since  135.8< 146 < 155.9

So , it is usual.

d. 155  

since 135.8< 1155 < 155.9

So , it is usual.

Hence, the correct answer is b. 134 .

4 0
3 years ago
Help me plz!!!!!!!!!!!!!
4vir4ik [10]
22 and 27 is the answer. what else do you need??
8 0
3 years ago
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