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masha68 [24]
3 years ago
11

SOMEONE PLEASE HELP ME WITH THIS QUESTION 2.5x - 3 = 2x - 2 I don't get what x is equal to

Mathematics
1 answer:
Luda [366]3 years ago
5 0

Answer:

2

Step-by-step explanation:

Use the property of equality :)

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Darla found that the least common denominator needed to subtract \frac{x}{x^2+4x-12}-\frac{3}{x+6}is (x + 6)(x – 2). Which is th
Leona [35]
<h3>Answer: Choice B</h3>

\frac{x}{(x+6)(x-2)} - \frac{3(x-2)}{(x+6)(x-2)}

which is the same as x/((x+6)(x-2)) - 3(x-2)/((x+6)(x-2))

=====================================

Explanation:

The LCD is (x+6)(x-2) which is the factorization of x^2+4x-12, and that is the denominator of the first fraction. The first fraction has the LCD already. The second fraction does not. It has (x+6) but it is missing (x-2).

We multiply top and bottom of the second fraction by (x-2) to get the second fraction to have the LCD.

\frac{3}{x+6} turns into \frac{3}{x+6}*\frac{x-2}{x-2} = \frac{3(x-2)}{(x+6)(x-2)}

------

So,

\frac{x}{x^2+4x-12} - \frac{3}{x+6}

\frac{x}{(x+6)(x-2)} - \frac{3}{x+6}

\frac{x}{(x+6)(x-2)} - \frac{3(x-2)}{(x+6)(x-2)}

This is the same as x/((x+6)(x-2)) - 3(x-2)/((x+6)(x-2))

Note the parenthesis around "(x+6)(x-2)"

Instead of x/(x+6)(x-2) you should write x/( (x+6)(x-2) ) to ensure that all of "(x+6)(x-2)" is in the denominator.

4 0
3 years ago
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