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vladimir2022 [97]

3 years ago

7

Renuka has two pounds of pepper in her cupboard. She knows that there are 16 ounces in one pound. After Renuka makes one batch o

f Garam Masala, how many ounces of pepper does Renuka have left in her cupboard?

1 answer:

IceJOKER [234]3 years ago

5 0

16*2=32
32-.25(1.5 teaspoons) =31.75
31.75 ounces of pepper

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Jack is in a helicopter and looking down at two friends’ homes. The angle of depression to the first home is 72°. The angle of d

alexandr402 [8]

The distance between the helicopter and the first home is 369. 87 m

<h3>How to solve the distance using the angle of depression?</h3>

The distance between the helicopter and the first home can be found using sine law,

Hence,

180 - 72 - 49 = 59 degrees.

Therefore,

420 / sin 59 = A / sin 49°

where

A = distance form the first home to the helicopter.

cross multiply

420 sin 49 = A sin 59°

A = 420 sin 49 / sin 59

A = 316.978023694 / 0.8571673007

A = 369.869339199

A = 369. 87 m

Therefore, the distance between the helicopter and the first home is 369. 87 m

learn more on angle of depression here: brainly.com/question/1976859

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5 0

2 years ago

For a school assembly student sit in chairs that are arranged in 53 rows. There are 12 chairs in each row. About how many studen

loris [4]

53x12=636 that is your answer that is the way to estimate it your answer is 636 that is how many students can be seated

6 0

3 years ago

Divide each polynomials by the monomials. Choose all that are correct. (9xy2 + 12x3y4 − 6x) ÷ 3x = 4x2y4 + 3y2 − 2 (25x4y2 + 10x

UkoKoshka [18]

Answer:

(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy

Step-by-step explanation:

(9xy^2 + 12x^3y^4 − 6x) ÷ 3x = 4x^2y^4 + 3y^2 − 2 (False: 9xy^2:3x=3y^2)

25x^4y^2 + 10x^2y^4 − 15y) ÷ 5y = 5x^4y + 2x^3y^2 − 3 (False: 10x^2y^4:5y=2x^2y^3)

(16x^4y^2 + 24x^2y^2 − 8xy^2) ÷ 4xy = 4x^4y + 6xy− 2y(False: 16x^4y^2:4xy=4x^3y)

(21x^4y + 7x^3y^2 − 28x^2y^2) ÷ 7xy = 3x^3 + x^2y − 4xy (True)

7 0

3 years ago

Match each set of vertices with the type of triangle they form.

Andrew [12]

Answer: The calculations are done below.

Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

$AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.$

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

$AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.$

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

$AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.$

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

$AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.$

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

$AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.$

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

4 0

3 years ago

Read 2 more answers

Solve the equation 4m = 28 for m.<br><br> A. 3<br> B. 4<br> C. 5<br> D. 7

Paha777 [63]

D 28/4=7 that is the answer for the question

3 0

3 years ago

Read 2 more answers