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Svetlanka [38]
3 years ago
12

Simplify the expression. -5(7m + 9) =

Mathematics
2 answers:
OlgaM077 [116]3 years ago
6 0

Answer:

Step-by-step explanation:

Here you go mate

Step 1

-5(7m + 9)  Equation/Question

Step 2

-5(7m + 9)  Simplify

(-5)(7m+9)

Step 3

(-5)(7m+9)  Multiply

-35m-45

Answer

-35m-45

Hope this helps

Schach [20]3 years ago
4 0

Answer:

Step-by-step explanation:

I can help

Step 1

-5(7m + 9)  Simplify

Step 2

-5(7m + 9)  use the law of distribution

-5*7m+(-5)*9

Step 3

-5*7m+(-5)*9  Simplify

Answer

-35m-45

Hope this helps

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Step-by-step explanation:

50/50 chance of choosing one or the other because there is only two options

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The moon is approximately 240,000 miles from the earth. What is the distance written in scientific notation?
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Hope This Helps You!
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6 0
3 years ago
Read 2 more answers
What is the primary goal and secondary goal of the Fried Liver Opening in chess? <br />
polet [3.4K]

Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.

Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.


3 0
3 years ago
What theorem shows that GTY=GUX?
wlad13 [49]

Answer:SAS

Step-by-step explanation:

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6 0
3 years ago
Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor
kenny6666 [7]

Answer:

a) 0.0167

b) 0

c) 5.948

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.16 ounces

Standard Deviation, σ = 0.08 ounces

We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) Standard deviation of 23 bags

\displaystyle\frac{S.D}{\sqrt{23}} = \frac{0.08}{\sqrt{23}} = 0.0167

b) P( fill volume of 23 bags is below 5.95 ounces)

P(x < 5.95)

P( x < 5.96) = P( z < \displaystyle\frac{5.95 - 6.16}{0.0167}) = P(z < -12.57)

= 1 - P(z < 12.57)

Calculation the value from standard normal z table, we have,  

P(x < 5.95) = 1 - 1 = 0

c) P( fill volume of 23 bags is below 6 ounces)  = 0.001

P(x < 6)  = 0.001

P( x < 6) = P( z < \displaystyle\frac{6 - \mu}{0.0167})

Calculation the value from standard normal z table, we have,  

P( z \leq -3.09) = 0.001

\displaystyle\frac{6 - \mu}{0.0167} = -3.09\\\\\mu = 6 + (0.0167\times -3.09) = 5.948

If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.

7 0
3 years ago
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