Step-by-step explanation:
50/50 chance of choosing one or the other because there is only two options
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Scientific notation is when the number is between 0 and 10 times 10 to a power.
In this case we'd get 2.4 x

.
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Play usually continues 7.Qf3+ Ke6 8.Nc3 (see diagram). Black will play 8...Nb4 or 8...Ne7 and follow up with c6, bolstering his pinned knight on d5. If Black plays 8...Nb4, White can force the b4 knight to abandon protection of the d5 knight with 9.a3?! Nxc2+ 10.Kd1 Nxa1 11.Nxd5, sacrificing a rook, but current analysis suggests that the alternatives 9.Qe4, 9.Bb3 and 9.O-O are stronger. White has a strong attack, but it has not been proven yet to be decisive.
Because defence is harder to play than attack in this variation when given short time limits, the Fried Liver is dangerous for Black in over-the-board play, if using a short time control. It is also especially effective against weaker players who may not be able to find the correct defences. Sometimes Black invites White to play the Fried Liver Attack in correspondence chess or in over-the-board games with longer time limits (or no time limit), as the relaxed pace affords Black a better opportunity to refute the White sacrifice.
Answer:SAS
Step-by-step explanation:
The line show congruent line which means two sides. Since it has vertical angles it has a angle.
Answer:
a) 0.0167
b) 0
c) 5.948
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 6.16 ounces
Standard Deviation, σ = 0.08 ounces
We are given that the distribution of fill volumes of bags is a bell shaped distribution that is a normal distribution.
Formula:
a) Standard deviation of 23 bags

b) P( fill volume of 23 bags is below 5.95 ounces)
P(x < 5.95)
Calculation the value from standard normal z table, we have,
c) P( fill volume of 23 bags is below 6 ounces) = 0.001
P(x < 6) = 0.001
Calculation the value from standard normal z table, we have,


If the mean will be 5.948 then the probability that the average of 23 bags is below 6.1 ounces is 0.001.