Answer:
Distance between school and home = 105 miles.
Step-by-step explanation:
Let distance = D miles
Time to take walking/jogging, t1 = D/6 hours
Time by car, t2 = D/35 hours
Average time, t
= (t1+t2)/2
= D(1/6+1/35)
= (D/210)(35+6)
=41D/210 hours
Given t = t1-3 hours
41D/210 - D/6 = 3
Solve for D
41D/210 - 35D/210 = 3
(41-35)D/210 = 3
6D/210 = 3
D = 3*210/6 = 105 miles.
(Appreciate very much Diana's efforts to walk/job 105 miles to school, and we understand how lucky we are in most of Europe and North America)
Answer: Choice B. The vertex is (6,-4)
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Work Shown:
Step 1 is to expand out (x-8)(x-4) using the FOIL rule or the box method or the distribution rule
(x-8)(x-4) = x(x-4)-8(x-4)
(x-8)(x-4) = x*x+x*(-4)-8*x-8*(-4)
(x-8)(x-4) = x^2-4x-8x+32
(x-8)(x-4) = x^2-12x+32
So (x-8)(x-4) turns into x^2-12x+32
x^2-12x+32 is the same as 1x^2+(-12x)+32 which is in the form ax^2+bx+c. We see that a = 1, b = -12, c = 32
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Use the values of a & b to find the value of h, which is the x coordinate of the vertex
h = -b/(2*a)
h = -(-12)/(2*1)
h = 12/2
h = 6
Then this is plugged back into the original function to find the y coordinate of the vertex. We can use either (x-8)(x-4) or x^2-12x+32 since they are equivalent expressions
k = y coordinate of vertex
k = f(h) = f(6) since h = 6
f(x) = (x-8)(x-4)
f(6) = (6-8)(6-4)
f(6) = (-2)(2)
f(6) = -4
note that
f(x) = x^2-12x+32
f(6) = (6)^2-12(6)+32
f(6) = 36-72+32
f(6) = -36+32
f(6) = -4
So we get the same result using either expression
So k = f(h) = f(6) = -4
Since h = 6 and k = -4, the vertex is (h,k) = (6,-4). So that's why the answer is choice B.
Answer:
For the two fractions 4/5 and 5/6, the least common denominator is 30. The fraction 4/5 is equivalent to 24/30 (To get this I multiplied both the numerator and denominator by 6). The fraction 5/6 is equivalent to 25/30 (To get this I multiplied both the numerator and denominator by 5).
Step-by-step explanation:
They are equivalent (Except for the numerator)
Answer:
c. 10 cm
Step-by-step explanation:
The parallel sides of trapizium are the bases so
base 1(B1) =9cm , base(B2)= 12cm

the perpendicular distance means the height so lets find the height
area of trapizium= <u>B1 + B2</u> × h
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2


now we crisscross



h = 10 cm
hope u like it ❤️❤️❤️
For any question comment me
Answer:
To be honeest i dont know
Step-by-step explanation: