Answer: Concentration of HI is present at equilibrium is 1.26 M
Explanation:
Moles of = 0.800 mole
Moles of = 0.800 mole
Volume of solution = 1.00 L
Initial concentration of = 0.800 M
Initial concentration of = 0.800 M
The given balanced equilibrium reaction is,
Initial conc. 0.800 0.800 0
At eqm. conc. (0.800-x) M (0.800-x) M (2x) M
The expression for equilibrium constant for this reaction will be,
Now put all the given values in this expression, we get :
By solving the term 'x', we get :
x = 0.63
Concentration of at equilibrium = 2 x =
Concentration of HI is present at equilibrium is 1.26 M