Question

PLEASE HELP ASAP WILL GIVE BRAINLIEST

Answer 1

The amount of heat required to convert H₂O to steam is :  382.62 kJ

Given data :

Mass of liquid water  ( m ) = 150 g

Temperature of liquid water = 43.5°C

Temperature of steam = 130°C

Determine the amount of heat required

The amount of heat required = ∑ q1 + q2 + q3 ----- ( 1 )

where ;

q1 = heat required to change Temperature of water from 43.5°C to 100°C .  q2 = heat required to change liquid water at 100°C to steam at 100°C

q3 = heat required to change temperature of steam at 100°C to 130°C

• For q1

M* S$_{water}$*ΔT

= 150 * 4.18 * ( 100 - 43.5 )

= 35425.5 J

• For q2

moles * ΔHvap

= (150 / 18 )* 40.67 * 1000

=  338916.67 J

• For q3

M * S$_{steam}$ * ΔT

= 150 * 1.84 * ( 130 -100 )

= 8280 J

Back to equation ( 1 )

Amount of heat required = 35425.5  + 338916.67 + 8280 = 382622.17 J

                                                                                               ≈ 382.62 kJ

Hence we can conclude that The amount of heat required to convert H₂O to steam is :  382.62 kJ.

Learn more about Specific heat of water : brainly.com/question/16559442