Answer:
13.
<S=½(arc TQ- arc TR)=½(143-71)=36°
14.
<E=½(arc DG- arc DF)=½(169-59)=55°
15.
arc PR=180-62=118°{sum of opposite angle of quadrilateral in circle is supplementary)
16.
arc TR =180-47=133°
again
arc T?R=360-133=227°
17.
62+38x+4=180
38x=180-66
x=114/38
x=3
The probability of getting all heads is 1 / 2^6 = 1/64 as there is only 1 event where this happens in a possible 2^6 = 64 events. It is the same as the probability of getting all tails. The probability of getting at least 1 head is 1 - p(all tails) = 63/64.
I’m not positive but the answer might be 240.34
Answer:
The polynomial of minimum degree is
.
Step-by-step explanation:
According to the statement, we appreciate that polynomial pass through the following points:
(i)
, (ii)
, (iii)
, (iv) 
From Algebra we know that any n-th grade polynomial can be constructed by knowing n+1 different points. Hence, the polynomial of minimum degree is a quartic function. The polynomial has the following form:

We proceed to expand the expression until standard form is obtained:




If we know that
, then:



Then, the polynomial is:



The polynomial of minimum degree is
.
√(4×18)= √72 or √36√2= 6√2 simplified