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Natali [406]
3 years ago
6

55/100 in simplest form

Mathematics
2 answers:
Svetradugi [14.3K]3 years ago
7 0
\frac{55}{100} = \frac{11\times 5}{20\times 5} = \huge{\boxed{\frac{11}{20}}}
mezya [45]3 years ago
3 0
Well 55 can be divided by 5 to get 11, same thing for 100 except you get 20. Plus you can not divide 11 any more so the answer is 11/20
You might be interested in
given the following information, determine which lines, if any, are parallel. state the converse that justifies your answer.
frozen [14]

From the information in the diagram found in a similar question online (please see attached drawing), the parallel lines are;

  1. w||z
  2. x||y
  3. x||y
  4. w||z
  5. w||z
  6. x||y
  7. x||y
  8. w||z
  9. x||y
  10. w||z

<h3>What are the relationships between angles formed by parallel lines?</h3>

Parallel lines are lines that do not meet, when extended indefinitely.

The possible information given as obtained from a similar question posted online are;

1. ‹1 is congruent to ‹5

2. ‹7 is congruent to ‹9

3. m‹8 + m‹9 = 180°

4. ‹16 is congruent to ‹14

5. m‹1 + m‹4 = 180°

6. ‹3 is congruent to ‹13

7. ‹2 is congruent to ‹10

8. ‹11 is congruent to ‹15

9. m‹4 + m‹13 = 180°

10. ‹8 is congruent to ‹6

1. Given that ‹1 is congruent to ‹5 where ‹1 and ‹5 are alternate exterior angles, we have that line <em>w </em>is parallel to line <em>z </em>

  • w||z

Theorem (converse); Alternate exterior angles formed by two parallel lines having a common transversal are congruent.

2. ‹7 and ‹9 are alternate interior angles.

Given that ‹7 is congruent to ‹9, therefore;

Line <em>x</em> is parallel to line <em>y</em>

  • x||y

Theorem (converse); Alternate interior angles formed by two parallel lines having a common transversal are congruent.

3. Given that m‹8 + m‹9 = 180°, therefore;

‹8 and ‹9 are supplementary angles, formed between lines <em>x </em>and <em>y</em>.

‹8 and ‹9 are also consecutive interior angles.

Theorem (converse); Consecutive interior angles formed between parallel lines are supplementary.

Therefore;

  • x||y

4. ‹16 and ‹14 are corresponding angles formed by lines <em>w </em>and <em>z</em>.

Theorem (converse); Corresponding angles formed by parallel lines are congruent.

Given ‹16 congruent to ‹14, we have;

  • w||z

5. m‹1 and m‹4 are consecutive exterior angles formed by lines <em>w </em>and <em>z</em>.

Theorem (converse); Consecutive exterior angles formed by two parallel lines are supplementary.

Given that m‹1 + m‹4 = 180°, we have;

  • w||z

6. ‹3 and ‹13 are alternate exterior angles formed by lines <em>x </em>and <em>y</em>.

Theorem (converse); Alternate exterior angles formed by parallel lines are congruent.

Given that ‹3 congruent to ‹13, we have;

  • x||y

7. ‹2 and ‹10 are corresponding angles formed by lines <em>x </em>and <em>y</em>

Given that ‹2 congruent to ‹10, therefore;

  • x||y

8. ‹11 and ‹15 are alternate interior angles formed by lines <em>w </em>and <em>z</em>.

‹11 is congruent to ‹15, therefore;

  • w||z

9. ‹4 and ‹13 are consecutive exterior angles formed by lines <em>x </em>and <em>y</em>

m‹4 + m‹13 = 180°, therefore;

  • x||y

10. ‹8 and ‹6 are corresponding angles formed by lines <em>w </em>and <em>z</em>.

‹8 is congruent to ‹6, therefore;

  • w||z

Learn more about angles formed by parallel lines that have a common transversal here:

brainly.com/question/24607467

#SPJ1

3 0
1 year ago
Need help ASAP
Tresset [83]

Answer:

upper left

Step-by-step explanation:

The generic equation for a circle centered at (h, k) with radius r is ...

(x -h)^2 +(y -k)^2 = r^2

Comparing that equation to the one you have, you can see that ...

-h = 0

-k = +3

r^2 = 9

Then you have (h, k) = (0, -3) and a radius of 3.

The circle has its center on the y-axis 3 units below the x-axis and just touches the x-axis. This is a description of the graph at upper left.

4 0
3 years ago
Differencee of 53/66-3/11
mars1129 [50]

Answer: 35/66 is your answer!

Step-by-step explanation:

8 0
3 years ago
Josie ran a lap in 45.23 seconds.
BlackZzzverrR [31]

Answer: 2.12 seconds

Step-by-step explanation:

From the question, we are informed that Josie ran a lap in 45.23 seconds while Erica ran a lap in 43.11 seconds.

To calculate the extra amount of time it took Josie to complete the lap, we subtract Erica's time from Josie's time. This will be:

= 45.23 seconds - 43.11 seconds

= 2.12 seconds

3 0
3 years ago
Calculate the rate of change.<br> 0    1   2    3    4   5<br> 15 25 40 60 85 115
Arte-miy333 [17]
Dy/dx=10,15,20,25,30

d2y/dx2=5,5,5,5,5  (there is no "rate of change" that is constant because acceleration is positive meaning that velocity keeps increasing...)

Since d2y/dx2 is constant, acceleration is constant, and this means that it is a quadratic equation of the form y=ax^2+bx+c

There are only three unknowns so we can use just three data points.

9a+3b+c=60
4a+2b+c=40
a+b+c=25  getting differences between these...

5a+b=20
3a+b=15  and again...

2a=5, so a=2.5, making 3a+b=15 become:

7.5+b=15, so b=7.5, making a+b+c=25 become:

2.5+7.5+c=25, so c=15

So the quadratic which produced the table is:

y=2.5x^2+7.5b+15

This is the regular old position function you see with any object moving with constant acceleration (like gravity when simplified).

The acceleration is 2.5 it has an initial velocity of 7.5 and an initial position of 15.
8 0
3 years ago
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