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ladessa [460]
3 years ago
15

The graph of a polynomial function continues down on the left and continues down on the right. Which of the following must be tr

ue about this polynomial function? The function is even with a positive leading coefficient.
The function is odd with a positive leading coefficient.
The function is even with a negative leading coefficient.
The function is odd with a negative leading coefficient.
Mathematics
1 answer:
lesya692 [45]3 years ago
4 0
The function is even with a negative leading coefficient.  Even means the tails both go the same way, negative means they both go down.
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Use Newton’s Method to find a solution of the equation e 6x+ 3(ln 2)2 e 2x− e 4x ln 8 − (ln 2)3 = 0 with error tolerance 10−5 ,
Afina-wow [57]

Answer:

  x ≈ -0.746756

Step-by-step explanation:

We have interpreted your equation to be ...

  e^{6x}+3\ln{(2)}^2e^{2x}-e^{4x\ln{(8)}}-\ln{(2)}^3=0

A graphing calculator shows the desired zero to be near -0.747. Using that value as the first guess in Newton's iteration formula, we find the next guess to be ...

  x ≈ -0.746756

Iterating another time gives a solution accurate to 12 significant digits. The above result is well within the allowed tolerance of 10^-5.

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Of course, you know that the Newton's Method iterator for finding the "next guess" is ...

  next guess = x - f(x)/f'(x)

where f'(x) is the derivative of f(x), and the value of x is the current guess.

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<em>Comment on this solution</em>

For the purposes of Newton's method a numerical estimate of the derivative of the function is sufficient. Most graphing calculators have a derivative function, so all you need to do is specify the function you want to evaluate the derivative of. You could go to the trouble to develop the exact formula for the derivative of this function, but it isn't necessary to obtain an answer that is close enough.

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We have shown two separate uses of the iteration function. In practice, this calculator (Desmos) gives the function result as you type the argument, so all you need to do is copy the function output to its input to obtain calculator accuracy (12 significant digits) in one pass. A calculator like a TI-84 can do a similar thing by making the first iteration, Y₂(-0.747), then repeatedly computing Y₂(Ans), that is, using the previous answer in the iteration function again. For that calculator, one additional iteration is all that is needed to get to its 10 significant digit limit.

3 0
4 years ago
The Hudson Valley Stadium Renegades has a capacity of maximum 4,505 people. During a the peak of its popularity, the tickets sol
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6 0
4 years ago
Evaluate the function
mars1129 [50]

Answer:

g (x) = 3x^2 − 2x + 5

Step-by-step explanation:

8 0
3 years ago
X/5-2=x/2+3 solve for x
Makovka662 [10]
Solve for x:x/5 - 2 = x/2 + 3
Put each term in x/5 - 2 over the common denominator 5: x/5 - 2 = x/5 - (10)/5:x/5 - (10)/5 = x/2 + 3
x/5 - (10)/5 = (x - 10)/5:(x - 10)/5 = x/2 + 3
Put each term in x/2 + 3 over the common denominator 2: x/2 + 3 = x/2 + 6/2:(x - 10)/5 = x/2 + 6/2
x/2 + 6/2 = (x + 6)/2:(x - 10)/5 = (x + 6)/2
Multiply both sides by 10:(10 (x - 10))/5 = (10 (x + 6))/2
10/5 = (5×2)/5 = 2:2 (x - 10) = (10 (x + 6))/2
10/2 = (2×5)/2 = 5:2 (x - 10) = 5 (x + 6)
Expand out terms of the left hand side:2 x - 20 = 5 (x + 6)
Expand out terms of the right hand side:2 x - 20 = 5 x + 30
Subtract 5 x from both sides:(2 x - 5 x) - 20 = (5 x - 5 x) + 30
2 x - 5 x = -3 x:-3 x - 20 = (5 x - 5 x) + 30
5 x - 5 x = 0:-3 x - 20 = 30
Add 20 to both sides:(20 - 20) - 3 x = 20 + 30
20 - 20 = 0:-3 x = 30 + 20
30 + 20 = 50:-3 x = 50
Divide both sides of -3 x = 50 by -3:(-3 x)/(-3) = 50/(-3)
(-3)/(-3) = 1:x = 50/(-3)
Multiply numerator and denominator of 50/(-3) by -1:Answer:  x = (-50)/3
7 0
3 years ago
Using the equation y= 2/3x -5, describe how to create a system of linear equations with and infinite number of solutions
IRISSAK [1]

Answer:

sorry but I do not now this any more but did once upon a time

Step-by-step explanation:

5 0
3 years ago
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