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3 years ago

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The graph of a polynomial function continues down on the left and continues down on the right. Which of the following must be tr

ue about this polynomial function? The function is even with a positive leading coefficient.
The function is odd with a positive leading coefficient.
The function is even with a negative leading coefficient.
The function is odd with a negative leading coefficient.

1 answer:

lesya692 [45]3 years ago

4 0

The function is even with a negative leading coefficient. Even means the tails both go the same way, negative means they both go down.

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Paraphin [41]

The area of a shape is the amount of space a shape can occupy, while the perimeter is the sum of its lengths.

<em>The perimeter is </em> $18 + 3\sqrt 5 + 3\sqrt 2$ <em>units</em>
<em>The area of the sanctuary is 27 square units</em>

We have:

$A = (5,7)\\B=(8, 7)\\C=(8, 1)\\D=( 1, 1)\\E=( 1, 4)\\F= ( 5,4)$

<u>Perimeter</u>

See attachment for the layout of the sanctuary

$BC = \sqrt{(8 - 8)^2 + (7 - 1)^2} = 6$

$EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4$

$FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3$

From the attachment, the sides are

<em>AB, BF, FC, CD, DE and EA</em>

Start by calculating the length of each side using the following distance formula:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_2)^2}$

So, we have:

$AB = \sqrt{(5 - 8)^2 + (7 - 7)^2} = 3$

$BF = \sqrt{(8 - 5)^2 + (7 -1)^2} = \sqrt{45} = 3\sqrt 5$

$FC = \sqrt{(8 - 5)^2 + (1 -4)^2} = \sqrt{18} = 3\sqrt 2$

$CD = \sqrt{(8 - 1)^2 + (1 - 1)^2} = 7$

$DE = \sqrt{(1 - 1)^2 + (1 - 4)^2} = 3$

$EA = \sqrt{(1 - 5)^2 + (4 -7)^2} = 5$

So, the perimeter (P) is:

$P = AB + BF + FC + CD + DE + EA$

$P = 3 + 3\sqrt 5 + 3\sqrt 2 + 7 + 3 + 5$

$P = 18 + 3\sqrt 5 + 3\sqrt 2$

<em>Hence, the perimeter is </em> $18 + 3\sqrt 5 + 3\sqrt 2$ <em>units</em>

<u />

<u>Area</u>

To calculate the area, we need to divide the sanctuary into three.

<em>Triangle ABF</em>
<em>Triangle EFA</em>
<em>Trapezium CDEF</em>

The area of ABF is:

$Area = \frac 12 \times AB \times FA$

Where:

$AB = 3$

$FA = \sqrt{(5 - 5)^2 + (4 - 7)^2} = 3$

$Area = \frac 12 \times 3 \times 3$

$Area = \frac 92$

The area of EFA is:

$Area = \frac 12 \times EF \times FA$

Where:

$FA = 3$

$EF = \sqrt{(1 - 5)^2 + (4 - 4)^2} = 4$

So:

$Area = \frac 12 \times 4 \times 3$

$Area = 6$

The area of CDEF is:

$Area = \frac 12(CD + EF) \times DE$

Where

$CD = 7$

$EF = 4$

$DE = 3$

So, we have:

$Area = \frac 12 (7 + 4) \times 3$

$Area = \frac 12 \times 11 \times 3$

$Area = \frac {33}2$

So, the area of the sanctuary is:

$Area = \frac 92 + 6 + \frac {33}2$

$Area = \frac {9 +12 + 33}2$

$Area = \frac {54}2$

$Area = 27$

<em>Hence, the area of the sanctuary is 27 square units</em>

Read more about areas and perimeters at:

brainly.com/question/11957651

8 0

3 years ago

Jimmy has a diecast metal car that is a scale model of an actual race car. If the actual length of the car is 10 feet 6 inches a

kirill115 [55]

The scale factor would be -8 because...

126 inches / 7 inches = 8 inches.

Because the car is bigger than the scale, it would be a negative scale factor.

8 0

3 years ago

Determine the period.

dimulka [17.4K]

Answer:

4

Step-by-step explanation:

The period is the length of one cycle.

By cycle, I mean the smallest piece that can be traced and copied over and over to form the whole graph. If you notice the graph starts at x=0 and the curve makes a complete cycle by x=4. The cycle starts over again at x=4 and ends at x=8. I hope you are seeing the graph looks exactly the same from x=0 to x=4 as x=4 to x=8.

The length of one cycle of this graph is 4.

Please let me know if you have further questions about this question.

Thank you.

8 0

3 years ago

Help Plz Due Tmrw. ......

romanna [79]

Answer:

i´ll help here

the smallest is (-3)^0

the second smallest or biggest is 16^1/2

the biggest one is (1/27)^-1/3

Step-by-step explanation:

hope this is correct

4 0

3 years ago

Read 2 more answers

A car travels along a straight line at a constant speed of 55.0 mi/h for a distance d and then another distance d in the same di

elena-14-01-66 [18.8K]

Answer:

a. 17.03 mi/hr b. 0 mi/hr or 18.99 mi/hr c. 17.03 mi/hr

Step-by-step explanation:

Av Vel =(V1+V2)/2 =26

Av Speed =d/t=55=> d=55t1

D=d+d 2d =2(55t1)=110t1

av Vel =110ti/(t1+t2)

t2=3.23t1 => total time =4.23 t1

a. V2=55t1/3.23t1 =17.03 mi/hr

b. velocity as vector quantity (v2-v1)/2 =18.88 or displacement d-d=0 and av velocity = (d-d)/2= 0/2

c. since all information are standing but opposite direction which doesn't affect speed as scalar av speed is the same

4 0

3 years ago