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Marrrta [24]
3 years ago
14

On a field trip, a student in a marine biology class collects an organism that has differentiated organs, cell walls of cellulos

e, and chloroplasts with chlorophyll a. Based on this description, the organism could be a brown alga, a red alga, a green alga, a charophyte recently washed into the ocean from a freshwater or brackish water source, or a land plant washed into the ocean. The presence of which of the following features would definitively identify this organism as a land plant?a.spindle fibers.b.embryosc.sporopollenin.d.lignin
Biology
1 answer:
Phoenix [80]3 years ago
8 0
B. Embryos are being collected by the student on the field trip.
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What can you see that plant is monocot or dicot​
garri49 [273]

Monocots differ from dicots in four distinct structural features: leaves, stems, roots and flowers.

But, the differences start from the very beginning of the plant's life cycle: the seed. Within the seed lies the plant's embryo. Whereas monocots have one cotyledon (vein), dicots have two. This small difference at the very start of the plant's life cycle leads each plant to develop vast differences.

5 0
3 years ago
What step in photosynthesis may occur during day and night?
Valentin [98]

Answer: During the day, photosynthesis is dominant, so there is a net release of oxygen. At night, photosynthesis stops but respiration continues, so there is a net consumption of oxygen.

Explanation:

4 0
2 years ago
You have been asked to lead a research team to observe gorillas in their natural environment, collect DNA samples, and analyze h
defon

Answer:

As i am asked to lead a research team to observe gorillas in their natural environment I will prefer a team having persons expert in having knowledge of forest in which we are doing research on gorillas. They must be experience in working with gorillas and familiar with their nature.

My team should have a person who know to use the tranquilizer gun because to collect the DNA sample gorilla needs to be tranquilized. My team should have one veterinary doctor who can examine the animal and take the DNA sample.

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8 0
3 years ago
The first glycolysis rate-limiting enzyme is under various allosteric regulations. This protein is nearly inactive because of in
navik [9.2K]

Answer:

d. ATP;  Fructose-2,6-bisphosphate

Explanation:

Phosphofructokinase-1 is the enzyme that catalyzes the formation of fructose-1,6-bisphosphate from fructose-6-phosphate and ATP. The phosphofructokinase step is the first rate-limiting step of glycolysis.

Phosphofructokinase-1 activity is allosterically regulated. Its activity is increased whenever the cell's ATP supply is depleted or when its breakdown products, ADP and AMP accuulates in he cell. However, it is inhibited when the cell is amply supplied with ATP.

The activity of phosphofructokinase-1 is restored by fructose-2,6-bisphosphate, its most potent activator.

From the given options:

a. AMP :::: citrate  is wrong because AMP increases the activity of phosphofructokinase-1 and citrate is not its activator but an inhibitor

b. AMP :::: Fru-2,6-P2  is wrong because AMP increases its activity same as fructose-2,6-bisphosphate

c. ATP :::: citrate  is wrong because both citrate and ATP are inhibitors

d. ATP :::: Fru-2,6-P2  is correct as explained above

e. All of these is wrong because of the other wrong options above.

6 0
3 years ago
Is sand alive according to the characteristics of life? Why or why not?
Vinvika [58]
No because it does not use energy, reproduce, have a metabolism, breathe, or maintain homeostasis and its not made up of cells.
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