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Katen [24]
3 years ago
5

What value of x makes this equation true?

Mathematics
1 answer:
Arlecino [84]3 years ago
5 0

Answer:

x = 4

Step-by-step explanation:

Given

13 - 4x = 1 - x ( add x to both sides )

13 - 3x = 1 ( subtract 13 from both sides )

- 3x = - 12 ( divide both sides by - 3 )

x = 4

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Negative numbers. Remember that whole numbers are 0 and positive numbers.
4 0
3 years ago
Which of the following are solution to 2X squared minus 8X -90
svetlana [45]

Answer:

2(x+5)*(x-9)

Step-by-step explanation:

4 0
3 years ago
What is 4 multiplied by 5 7/9 as a mixed number or fraction
Andrei [34K]
The answer is 23 and 1÷9

First you multiply 4 by 5 and wind up with 20
Then you multiply four by 7÷9.
That gets you 28÷9
You take out all the nines you can from 28, three in this case.
That gets you 27÷9 + 1÷9
Your total thing is 20+27÷9+1÷9
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8 0
3 years ago
Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

\tan \theta = \frac{\sin \theta}{\cos \theta}

From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

⇒\sin \theta = -\frac{3}{5}

now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

7 0
3 years ago
Write the inequality for the graph.
Slav-nsk [51]

9514 1404 393

Answer:

  -1 < x < 2

Step-by-step explanation:

The graph indicates the variable may take on values between -1 and 2, not including those values. The compound inequality is written ...

  -1 < x < 2

6 0
3 years ago
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