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yuradex [85]
3 years ago
10

Please help me. Thank you--

Mathematics
1 answer:
Lapatulllka [165]3 years ago
6 0
For the first one:tick the second to last.
for the second: tick the first circle.
for the third: tick the second to last.
for the forth: tick the second.
for the fifth: tick the last.
for the last one: tick the second.

Hope it helps...
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Answer:

Step-by-step explanation:

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Consider the following problem: A farmer with 750 ft of fencing wants to enclose a rectangular area and then divide it into four
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Answer and step-by-step explanation:

For any rectangle, the one with the largest area will be the one whose dimensions are as close to a square as possible.

However, the dividers change the process to find this maximum somewhat.

Letting x represent two sides of the rectangle and the 3 parallel dividers, we have 2x+3x = 5x.

Letting y represent the other two sides of the rectangle, we have 2y.

We know that 2y + 5x = 750.

Solving for y, we first subtract 5x from each side:

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Next we divide both sides by 2:

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y = -2.5x + 375

We know that the area of a rectangle is given by

A = lw, where l is the length and w is the width.  In this rectangle, one dimension is x and the other is y, making the area

A = xy

Substituting the expression for y we just found above, we have

A = x(-2.5x+375)

A = -2.5x² + 375x

This is a quadratic equation, with values a = -2.5, b = 375 and c = 0.

To find the maximum, we will find the vertex.  First we find the axis of symmetry, using the equation

x = -b/2a

x = -375/2(-2.5) = -375/-5 = 75

Substituting this back in place of every x in our area equation, we have

A = -2.5x² + 375x

A = -2.5(75)² + 375(75) = -2.5(5625) + 28125 = -14062.5 + 28125 = 14062.5

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3 years ago
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soh cah toa

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