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2 years ago

_ Ba(OH)2 + _ H3PO4 ----> _ BaHPO4 + _ H2O can someone please balance this?

Mathematics

1 answer:

Colt1911 [192]2 years ago

8 0

Answer:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Step-by-step explanation:

Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 3 atoms of Ba on the right side and 1atom on the left side. It can be balance by putting 3 in front of Ba(OH)2 as shown below:

3Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 2 atoms of P on the right side and 1atom on the left. It can be balance by putting 2 in front of H3PO4 as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + H2O

Now, there are a total of 12 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 6 in front of H2O as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Now the equation is balanced as the numbers of the atoms of the different elements present on both sides are equal

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3 years ago

Identify the center and radius from the equation of the circle given below. x^2+y^2+121-20y=-10x

Tcecarenko [31]

Answer:

Center: (-5,10)

Radius: 2

Step-by-step explanation:

The equation of the circle in center-radius form is:

$(x-h)^2+(y-k)^2=r^2$

Where the point (h,k) is the center of the circle and "r" is the radius.

Subtract 121 from both sides of the equation:

$x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121$

Add 10x to both sides:

$x^2+y^2-20y+10x=-10x-121+10x\\x^2+y^2-20y+10x=-121$

Make two groups for variable "x" and variable "y":

$(x^2+10x)+(y^2-20y)=-121$

Complete the square:

Add $(\frac{10}{2})^2=5^2$ inside the parentheses of "x".

Add $(\frac{20}{2})^2=10^2$ inside the parentheses of "y".

Add $5^2$ and $10^2$ to the right side of the equation.

Then:

$(x^2+10x+5^2)+(y^2-20y+10^2)=-121+5^2+10^2\\(x^2+10x+5^2)+(y^2-20y+10^2)=4$

Rewriting, you get that the equation of the circle in center-radius form is:

$(x+5)^2+(y-10)^2=2^2$

You can observe that the radius of the circle is:

$r=2$

And the center is:

$(h,k)=(-5,10)$

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3 years ago

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___ Ba(OH)2 + ___ H3PO4 ----> ___ BaHPO4 + ___ H2O can someone please balance this?

_ Ba(OH)2 + _ H3PO4 ----> _ BaHPO4 + _ H2O can someone please balance this?