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2 years ago

(why is it always math?)

Mathematics

2 answers:

romanna [79]2 years ago

5 0

Answer: omg I didn’t mean to post so now I’m editing it

kow [346]2 years ago

3 0

Answer:

B. 54.12x38=2056.56 dollars to fill up 38 gallons.

Step-by-step explanation:

BOKU NO HERO ACADEMIA WOOOO

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What is an equation of the line with slope 3 that goes through point (2/3, 4)

qwelly [4]

A. All the equations are in slope intercept form, so all that's needed to do is plug in 2/3 as the x value in each equation and if the result is 4, then you got the answer.

6 0

2 years ago

Solve for x sim b (10, 0.75) for x = 5

Aleksandr-060686 [28]

The value of $x \sim B (10, 0.75)$ for x = 5 is 0.06

<h3>How to solve the probability?</h3>

The expression is given as:

$x \sim B (10, 0.75)$

This means that:

n = 10

p = 0.75

The probability is then calculated as

$P(x)= ^nC_x * p^x *(1 - p)^{n-x$

This gives

$P(5)= ^{10}C_5 * 0.75^5 *(1 - 0.75)^5$

Evaluate the combination expression

$P(5)= 252 * 0.75^5 *0.25^5$

Evaluate

P(5)= 0.06

Hence, the value of $x \sim B (10, 0.75)$ for x = 5 is 0.06

Read more about probability at:

brainly.com/question/24756209

#SPJ1

6 0

1 year ago

If f(x)=x-2, which of the following is the inverse of F(x)

sergiy2304 [10]

The answer would be 2. This is because inverse means opposite, and since f(x)=-2, then that means the inverse would be 2.

5 0

2 years ago

Read 2 more answers

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :