Answer: the anwser is A
Step-by-step explanation:
I used a calculator lol
Your graph should look something like the one below, an exponential function (this is because your are raising a number to the power of x.
:)
Firstly, put Derek and Paul's collection together:
1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910, 1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920
1950+1952+1908+1902+1955+1954+ 1901+1910+1929+1935+1928+1930+ 1925+ 1932+1933+1920
=30864
=30864÷16
=1929
∴the mean is 1929.
Median:
1901, 1902, 1908, 1910, 1920, 1925, 1928, 1929, 1930, 1932, 1933, 1935,
1950, 1952, 1954, 1955
1930÷1929
=1.0005184
= Median
Range:
1955-1901
=54
∴the range is 54.
Mode is the most.
What number appears the most? 8. 8 appears twice.
Mean is the average.
Add up all the numbers. 5+8+16+14+2+18+8=71
Then divide by how many numbers there are. 71/7=10.1
Median is alway in-between.
If you set up a number line in order of least to greatest, what number is in the middle?
2,5,8,8,14,16,18
we can erase the numbers on each end to find the middle.
2,5,8,8,14,16,18
5,8,8,14,16
8,8,14,16
8,14
Uh oh! There are two numbers in the middle. In this case you find the average of these two numbers.
8+14= 22
22/2=11
The range is the highest number in your set of data minus the lowest number in your set of data.
So, 18-2=16
In conclusion...
Mode:8
Mean:10.1
Median:11
Range:16