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Ganezh [65]
3 years ago
9

Please provide steps

Mathematics
1 answer:
pentagon [3]3 years ago
5 0

1. 15 - 45 age range was the highest in attendance.

2. There are 20 people were between the ages of 5 and 15.

Solution:

The given image is a bar graph of ages of people attending a party.

(1) Highest attendance in age range:

In the bar graph, see the ages of highest pillars.

15 - 25, 25 - 35 and 35 - 45

Starting highest age 15.

Ending highest age 45.

So that 15 - 45 age range was the highest in attendance.

(2) In the 5 - 15 age pillar, see the corresponding frequency.

Frequency is 20.

So, there are 20 people were between the ages of 5 and 15.

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I really need some help. I need to find the inverse of this equation in the picture below. Thanks!
serg [7]

Answer:

y=81x^4+648x^3+1944x^2+2592x+1289

Step-by-step explanation:

1. Interchange x and y.

  • y=\frac{\sqrt[4]{x+7}}{3}-2
  • x=\frac{\sqrt[4]{y+7}}{3}-2

2. Then solve x=\frac{\sqrt[4]{y+7}}{3}-2 for y.

3. y=81x^4+648x^3+1944x^2+2592x+1289

I hope this helps.

4 0
2 years ago
What is the answer to the problem
vovikov84 [41]

Answer: 6

Step-by-step explanation: DE is 4+2 so EF would be the same if it is equal.

3 0
3 years ago
Does anyone know what this question means?
ioda

Answer:

Yes

Step-by-step explanation:

I know what it means. Trust me. I know.

7 0
3 years ago
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A good friend of yours
KATRIN_1 [288]
Sorry i have learnt it but i can remember how to do it

5 0
3 years ago
Plzz look into the question in the attachements
iren2701 [21]

Given : Diameter of the right circular cone ==> 8 cm

It means : The Radius of the right circular cone is 4 cm (as Radius is half of the Diameter)

Given : Volume of the right circular cone ==> 48π cm³

We know that :

\bigstar \ \ \boxed{\textsf{Volume of a right circular cone is given by : $\pi r^2\dfrac{h}{3}$}}

where : r is the radius of the circular cross-section.

             h is the height of the right circular cone.

Substituting the respective values in the formula, we get :

\mathsf{\implies \pi \times (4)^2 \times \dfrac{h}{3} = 48\pi}

\mathsf{\implies 16 \times \dfrac{h}{3} = 48}

\mathsf{\implies \dfrac{h}{3} = 3}

\implies \boxed{\mathsf{h= 9 \ cm}}

<u>Answer</u> : Height of the given right circular cone is 9 cm

8 0
3 years ago
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