Suppose R = {1,3,5,7,9,11,13,15,17} and D={3,6,9,12,15,18,21,24,27} r d

Mathematics

1 answer:

Free_Kalibri [48]1 year ago

3 0

The intersection of sets R and D is give by the following set:

R ∩ D = {3, 9, 15}.

<h3>What is the missing information?</h3>

This problem is incomplete, but researching it on a search engine, we find that it asks the intersection of sets R and D.

<h3>What is the set that is the intersection of two sets?</h3>

The set that is the intersection of two sets is composed by the elements that belong to both sets.

For this problem, the sets are given as follows:

R = {1,3,5,7,9,11,13,15,17}.

D={3,6,9,12,15,18,21,24,27}

Hence the intersection is given by:

R ∩ D = {3, 9, 15}.

As the elements 3, 9 and 15 are the only ones that belong to both sets.

More can be learned about intersection of sets at brainly.com/question/11439924

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According to a poll, 83% of California adults (418 out of 506 surveyed) feel that education is one of the top issues facing Cali

SpyIntel [72]

Answer:

A point estimate for the true population proportion is $\hat{p} = 0.83$ and the 90% confidence interval is (0.8025, 0.8575)

Step-by-step explanation:

We have a large sample of people of size n = 506. Let X be the random variable that represents the number of adults who feel that education is one of the top issues facing California. We are interested in the unknown true proportion p of adults who feel that education is one of the top issues facing California. A point estimate for the true population proportion is given by $\hat{p}$ = X/n = 418/506 = 0.83, the standard deviation is given by $\sigma_{\hat{p}} = \sqrt{p(1-p)/n}\approx\sqrt{\hat{p}(1-\hat{p})/n} = \sqrt{(0.83)(0.17)/506} = 0.0167$ . Therefore, the 90% confidence interval for the true population proportion is $\hat{p}\pm z_{0.1/2}\sqrt{\hat{p}(1-\hat{p})/n}$ , i.e., $0.83\pm z_{0.05}0.0167$ , i.e., $0.83\pm (1.6448)(0.0167)$ , (0.8025, 0.8575).