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GalinKa [24]
1 year ago
11

Suppose R = {1,3,5,7,9,11,13,15,17} and D={3,6,9,12,15,18,21,24,27} r d

Mathematics
1 answer:
Free_Kalibri [48]1 year ago
3 0

The intersection of sets R and D is give by the following set:

R ∩ D = {3, 9, 15}.

<h3>What is the missing information?</h3>

This problem is incomplete, but researching it on a search engine, we find that it asks the intersection of sets R and D.

<h3>What is the set that is the intersection of two sets?</h3>

The set that is the intersection of two sets is composed by the elements that belong to both sets.

For this problem, the sets are given as follows:

  • R = {1,3,5,7,9,11,13,15,17}.
  • D={3,6,9,12,15,18,21,24,27}

Hence the intersection is given by:

R ∩ D = {3, 9, 15}.

As the elements 3, 9 and 15 are the only ones that belong to both sets.

More can be learned about intersection of sets at brainly.com/question/11439924

#SPJ1

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Dovator [93]

Answer:

(x+2)(3x+1) are the factors

3 0
3 years ago
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Solve for the unknown values <br><br> X = ?<br> Y = ?
vovikov84 [41]

Step-by-step explanation:

So 95 is a linear pair. a linear pair adds up to 180 so 180 - 95 = 85

X = 85

y = 50

5 0
3 years ago
Acertijo.
Cerrena [4.2K]

La edad de cada uno de los integrantes del acertijo es:

  • <u>Luisa = 3 años </u>
  • <u>Juan = 6 años </u>
  • <u>Carmen = 8 años</u>

<em>Cálculo por medio de ecuaciones y el </em><em>método de igualación</em>.

Haciendo uso de la información brindada en el ejercicio, se procede a formular variables con las cuales se calcularán las ecuaciones, por lo tanto:

  • <em>X = Edad de Luisa</em>
  • <em>Y = Edad de Juan</em>
  • <em>Z = Edad de Carmen</em>

Con el enunciado: <em>"Luisa es 3 años más joven que su hermano Juan"</em> se crea la primera ecuación:

  • 1. Y = X + 3

Con el enunciado: <em>"Su hermana Carmen es 2 años mayor que Juan"</em>, se crea la segunda ecuación:

  • 2. Z = Y + 2

Y con el enunciado: <em>"Juan tiene el doble de edad que Luisa"</em>, se crea la tercera ecuación:

  • 3. X = \frac{Y}{2}

Ahora, utilizando el método de igualación, se reemplaza la <em>tercera ecuación en la primera</em>:

  • Y = X + 3
  • Y = (\frac{Y}{2}) + 3

Y se procede a sumar:

  • Y = (\frac{Y}{2}) + 3
  • Y = \frac{Y+6}{2}

El dividendo se pasa al otro lado de la igualdad a multiplicar:

  • 2Y = Y + 6

Y la variable "Y" que está sumando, se pasa al otro lado de la igualdad a restar:

  • 2Y - Y = 6
  • <u>Y = 6</u>

Con el valor de Y (edad de Juan) <em>se calcula X con la tercera ecuación</em>:

  • X = \frac{Y}{2}
  • X = \frac{6}{2}
  • <u>X = 3</u>

Una vez calculado el valor de X (edad de Luisa), se procede a <em>calcular el valor de Z con la segunda ecuación</em>:

  • Z = Y + 2
  • Z = 6 + 2
  • <u>Z = 8</u>

Por lo tanto, se calcula que <u>la edad de Luisa es 3 años, la edad de Juan es 6 años y la edad de Carmen es 8 años</u>.

Más información sobre ecuaciones:

brainly.com/question/15415929?referrer=searchResults

8 0
3 years ago
Please help need a 100
aivan3 [116]

I'd have to say it's A. Please don't blame me if I'm wrong. :)

4 0
3 years ago
Please help !! i need to know how to solve it.
Vera_Pavlovna [14]

We can determine the value of the adult ticket cost and student ticket cost by following these steps:

1. solve form one of the variables from one of the equations

Let's solve for a from 2a + 2s = 40

2a + 2s = 40

2a + 2s - 2s = 40 - 2s

2a = 40 - 2s

2a/2 = 40/2 - 2s/2

a = 20 - s

2. Replace the expression found and solve for s

4a + 5s = 87

4(20 - s) + 5s = 87

4×20 - 4×s + 5s = 87

80 - 4s + 5s = 87

80 + s = 87

80 - 80 + s = 87 - 80

s = 7

3. Replace 7 for s into a = 20 - s

a = 20 - 7

a = 13

Then, a = 13 and s = 7.

Then the adult ticket cost is $13 and the student ticket cost is $7

3 0
1 year ago
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