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Margaret [11]
3 years ago
12

I need help “ write the following answer as a fraction :

Mathematics
2 answers:
lubasha [3.4K]3 years ago
5 0

Answer:

1/16

Step-by-step explanation:

Dovator [93]3 years ago
3 0

Answer:F -4/2

Step-by-step explanation:

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This is for Pre-Calc, so please use Pre-Calc terms. You do not have to answer number 1. I have it done already. I need help ASAP
Dominik [7]

Answer:

17

Step-by-step explanation:

a1=2a7 because the square route of (Tan) is 49 so it 2a7tan49 fa10 the answer is b

6 0
3 years ago
Find the solution to the equations. 2x - y = -3 x y = 0 (0, 0) (-1, 1) (1, -1)
rosijanka [135]
(2x-y = -3 × y = 0 × (0, 0) × ( -1, 1) × (1, -1) = (2x - y = -3 × y =0 × (0)) ×, × 0 ×, × 1 ×, × -1
4 0
3 years ago
Which pair of equations represents two perpendicular lines? <br>answers shown in picture. ​
kolezko [41]

Answer:

y =1/2x+6

y = -2x+2

Step-by-step explanation:

Perpendicular line have slopes that multiply to -1

The slopes are negative reciprocals

-4*4 = 16  not perpendicular

1/2 * -2 = -1  perpendicular

1/5 *5 = 1  not perpendicular

2/3 * 2/3 = 4/9  not perpendicular

3 0
3 years ago
PLEASEEE HELPPPPPPP 15 POINTS
anygoal [31]
The equivalent to (1/3)^3 is

(1/3) x (1/3) x (1/3) = .<span>037
</span>
The answer is 1/27 or 0.37.
3 0
2 years ago
The volume
Sedaia [141]
\bf \begin{array}{cccccclllll}&#10;\textit{something}&&\textit{varies directly to}&&\textit{something else}\\ \quad \\&#10;\textit{something}&=&{{ \textit{some value}}}&\cdot &\textit{something else}\\ \quad \\&#10;y&=&{{ k}}&\cdot&x&#10;&&  y={{ k }}x&#10;\end{array}\\ \quad \\&#10;

and also

\bf \begin{array}{llllll}&#10;\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\&#10;\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\&#10;y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}&#10;&&y=\cfrac{{{  k}}}{x}&#10;\end{array}&#10;

now, we know that V varies directly to T and inversely to P simultaneously
thus\bf V=T\cdot \cfrac{k}{P}

so     \bf V=T\cdot \cfrac{k}{P}\qquad &#10;\begin{cases}&#10;V=42\\&#10;T=84\\&#10;P=8&#10;\end{cases}\implies 42=\cfrac{84k}{8}\implies 4=k&#10;\\\\\\&#10;V=\cfrac{4T}{P}\qquad now\quad &#10;\begin{cases}&#10;V=74\\&#10;P=10&#10;\end{cases}\implies 74=\cfrac{4T}{10}\implies 185=T
7 0
3 years ago
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