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3 years ago

6

The difference of twice a number and 3 is at most -21

1 answer:

Dmitrij [34]3 years ago

6 0

Answer:

The equation: 2<em>n</em> - 3 ≤ -21

The answer to the equation: <em>n</em> ≤ 9

Step-by-step explanation:

How to get the equation:

<u>The difference of</u> symbolizes subtraction. Because we are subtracting twice a number and 3, the first part of the equation can be written as 2<em>n</em> - 3. The <em>n</em> symbolizes the number.

<u>is at most</u> symbolizes a less than or equal to sign. That sign is ≤. And what is it less than or equal to? -21.

Now are equation is 2<em>n</em> - 3 ≤ -21

How to solve it:

2<em>n</em> - 3 ≤ -21

Add 3 to both sides of the equation

2<em>n</em> ≤ 18

Divide both sides of the equation by 2

<em>n</em> ≤ 9

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Step-by-step explanation:

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3 years ago

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-BARSIC- [3]

Answer

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Step-by-step explanation:

Write al the sides together: 2x + 5 + x^2 - 6 + 4x^2 + 2x + x^2 - 3x

Then organize the terms: 2x + 2x - 3x + 5 - 6 + x^2 + x^2 + 4x^2

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3 years ago

consider gk located at g (0,0) and k (4,4). describe the dilation of gk by a scale factor of 2 centered at (-2,-4)

KonstantinChe [14]

Solution: The dilation of gk by a scale factor of 2 centered at (-2,-4) is $g'(2,4)$ and $k'(10,12)$ .

Explanation:

It is given that the scale factor is 2 and center of dilation is (-2,-4).

If the center of dilation is (a,b) with scale factor k, then the dilation of a point P(x,y) is determined by the given formula.

$D(x,y)=(a+k(x-a),b+k(y-b))$ .....(1)

To find the g' substitute x=0, y=0, a=-2, b=-4 and k=2 in equation (1).

$g'=(-2+2(2),-4+2(4))\\g'=(2,4)$

To find the k' substitute x=4, y=4, a=-2, b=-4 and k=2 in equation (1).

$k'=(-2+2(4+2),-4+2(4+4))\\g'=(10,12)$

Therefore, the dilation of gk by a scale factor of 2 centered at (-2,-4) is $g'(2,4)$ and $k'(10,12)$ .

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