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1 year ago

Help QUICKKKKK please

Mathematics

1 answer:

Svetllana [295]1 year ago

5 0

Answer:

Step-by-step explanation:

Remark

The exposed perimeter of the triangle is just the two smaller legs of the right triangle (6 + 8) + 10 units at the bottom of the rectangle + two 1/2 circles.

The area of the figure is the area of the triangle at the top + the area of the two 1/2 circles + the rectangle in the middle.

Givens

Shortest Triangle Leg = 6
Middle Triangle Leg = 8
Diameter of the 2 half circles
pi = 3.14
width of the rectangle in the middle = 8
Length of the rectangle = 10
d = 8
r = d/2 = 8/2 = 4

Formula

Perimeter = 2 legs of the triangle + 2 half circles + bottom line

Area = (1/2) Leg1*leg2 + pi * r^2 + L * w

Solution

A Perimeter

Perimeter = 6 + 8 + 2*pi *r + 10

Perimeter = 24 + 2*3.14*4

Perimeter = 25.12

B Area

Area = 1/2 * 8 * 6 + 3.14*4^2 + 10* 8

Area = 24 + 50.24+ 80

Area = 150.24

Answer

P = 25.12

Area = 150.24

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Answer-

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2 years ago

What is the sum of the first 12 terms in the fibonacci sequence?

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Hello,

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$

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Step-by-step explanation:

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Step-by-step explanation:

An urn contains two blue balls (denoted $B_1 \:and\: B_2$ ) and three white balls (denoted $W_1, W_2 \:and\: W_3$ ).

In the selection, a ball is picked and replaced.

From the attached probability tree, the possible outcomes are:

$B_1B_1,B_1B_2,B_1W_1,B_1W_2,B_1W_3\\B_2B_1,B_2B_2,B_2W_1,B_2W_2,B_2W_3\\W_1B_1,W_1B_2,W_1W_1,W_1W_2,W_1W_3\\W_2B_1,W_2B_2,W_2W_1,W_2W_2,W_2W_3\\W_3B_1,W_3B_2,W_3W_1,W_3W_2,W_3W_3$

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Number of Outcomes =10

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(b)If only white balls are drawn

Number of Outcomes =9

Probability that only white balls are drawn $=\dfrac{9}{25}$

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