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castortr0y [4]
2 years ago
13

Need answer fast with all the steps included please

Mathematics
1 answer:
marysya [2.9K]2 years ago
6 0

Answer:

(\frac{6x^2y}{5})

Step-by-step explanation:

Given

\frac{(2x)(3x^3y^2)}{5x^2y}

Required

Solve

Open the brackets

\frac{(2x)(3x^3y^2)}{5x^2y} = \frac{(2x*3x^3y^2)}{5x^2y}

\frac{(2x)(3x^3y^2)}{5x^2y} = \frac{(6x^4y^2)}{5x^2y}

Apply law of indices:

\frac{(2x)(3x^3y^2)}{5x^2y} = \frac{(6x^{4-2}y^{2-1})}{5}

\frac{(2x)(3x^3y^2)}{5x^2y} = \frac{(6x^2y)}{5}

\frac{(2x)(3x^3y^2)}{5x^2y} = (\frac{6x^2y}{5})

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