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3 years ago

Need answer fast with all the steps included please

Mathematics

1 answer:

marysya [2.9K]3 years ago

6 0

Answer:

$(\frac{6x^2y}{5})$

Step-by-step explanation:

Given

$\frac{(2x)(3x^3y^2)}{5x^2y}$

Required

Solve

Open the brackets

$\frac{(2x)(3x^3y^2)}{5x^2y}$ = $\frac{(2x*3x^3y^2)}{5x^2y}$

$\frac{(2x)(3x^3y^2)}{5x^2y}$ = $\frac{(6x^4y^2)}{5x^2y}$

Apply law of indices:

$\frac{(2x)(3x^3y^2)}{5x^2y}$ = $\frac{(6x^{4-2}y^{2-1})}{5}$

$\frac{(2x)(3x^3y^2)}{5x^2y}$ = $\frac{(6x^2y)}{5}$

$\frac{(2x)(3x^3y^2)}{5x^2y}$ = $(\frac{6x^2y}{5})$

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