Answer:
No
Step-by-step explanation:
First solve both equations:
1) 9x = 5x + 4
Simplifying
9x = 5x + 4
Reorder the terms:
9x = 4 + 5x
Solving
9x = 4 + 5x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-5x' to each side of the equation.
9x + -5x = 4 + 5x + -5x
Combine like terms: 9x + -5x = 4x
4x = 4 + 5x + -5x
Combine like terms: 5x + -5x = 0
4x = 4 + 0
4x = 4
Divide each side by '4'.
x = 1
Simplifying
x = 1
2) 14x = 4
14x = 4 (divide both sides by 14 to get x)
14x/14 = 4/14
x = 0.285714285714
As you can see, the value of x in the second equations is less than one, therefore making these algebraic equations not equivalent.
Answer: Larger the MAD tells us that the ages of swimmer are far from the mean age. Thus means is not a relevant indicator for the data.
Step-by-step explanation:
We know that the mean absolute deviation (MAD) helps to know whether the mean of a data is a worthy indicator for the data values .
The larger the MAD tells us the values are spread out far from the mean .
Also, larger the MAD makes the mean less worthy as an indicator of the data elements within the data set.
Answer:
x = 13
Step-by-step explanation:
No se exactamente como decir esto porque yo ayudo la majoria de los usuario en ingles pero hay que usar un método para describir a x
Un método que se llama Pythagorean theorem
Pythagorean theorem: a^2 + b^2 = c^2 donde a^2 = 5 b^2 = 12 y c^2 = x
Entonces…
5^2 + 12^2 = c^2
Nota: podemos ver que esto esta bien porque el sum de los dos lados suma el mas largo.
Ahora
25 + 144 = c^2
c^2 = 169
Pero eso no puede ser la respuesta porque no tiene sentido a que x sea un lado que mide 169 entonces tenemos que usar sqrt rt
sqrt rt de 169 = 13
x = 13
Answer:
When we have something like:
![\sqrt[n]{x}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D)
It is called the n-th root of x.
Where x is called the radicand, and n is called the index.
Then the term:
![\sqrt[4]{16}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D)
is called the fourth root of 16.
And in this case, we can see that the index is 4, and the radicand is 16.
At the end, we have the question: what is the 4th root of 16?
this is:
![\sqrt[4]{16} = \sqrt[4]{4*4} = \sqrt[4]{2*2*2*2} = 2](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B16%7D%20%3D%20%5Csqrt%5B4%5D%7B4%2A4%7D%20%20%3D%20%5Csqrt%5B4%5D%7B2%2A2%2A2%2A2%7D%20%3D%202)
The 4th root of 16 is equal to 2.
Answer:
3
Step-by-step explanation:
Get rid of fractions:
Multiply the whole equation, i.e. all terms both sides of the equals sign, by the denominator or the lowest common multiple of all denominators if there are multiple fractions in the equation;
In this case, only one term is a fraction and therefore has a denominator (i.e. 7), so it is this number we multiply the equation by to get:
7(y) = 7(-³/₇.x) + 7(3)
7y = -3x + 21
3x + 7y = 21
