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kicyunya [14]
2 years ago
7

The formula = () − applies to the demand of a product, where q is the number of units and P is the price of one unit. How many u

nits will be demanded if the price is Rs. 18.00?
Mathematics
1 answer:
UNO [17]2 years ago
3 0

Answer:

4320 units quantities were demanded

Step-by-step explanation:

Given:

p = 90 (5) - \frac{q}{10}

Required:

The units demanded when price = 18.00

This implies that:

p = 18.00

So, we have:

p = 90 (5) - \frac{q}{10}

18.00 = 90(5) - \frac{q}{10}

Open bracket

18.00 = 450 - \frac{q}{10}

Collect like terms

\frac{q}{10} = 450 - 18.00

\frac{q}{10} = 432

Solve for q

q = 432 *10

q = 4320

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-3(u+2)=5u-1+5(2u+1)
Mazyrski [523]

Answer:

u = -5/9

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

-3(u + 2) = 5u - 1 + 5(2u + 1)

<u>Step 2: Solve for </u><em><u>u</u></em>

  1. Distribute:                             -3u - 6 = 5u - 1 + 10u + 5
  2. Combine like terms:             -3u - 6 = 15u + 4
  3. Add 3u to both sides:          -6 = 18u + 4
  4. Subtract 4 on both sides:    -10 = 18u
  5. Divide 18 on both sides:      -10/18 = u
  6. Simplify:                                -5/9 = u
  7. Rewrite:                                 u = -5/9

<u>Step 3: Check</u>

<em>Plug in u into the original equation to verify it's a solution.</em>

  1. Substitute in <em>u</em>:                     -3(-5/9 + 2) = 5(-5/9) - 1 + 5(2(-5/9) + 1)
  2. Multiply:                                -3(-5/9 + 2) = -25/9 - 1 + 5(-10/9 + 1)
  3. Add:                                      -3(13/9) = -25/9 - 1 + 5(-1/9)
  4. Multiply:                                -13/3 = -25/9 - 1 - 5/9
  5. Subtract:                               -13/3 = -34/9 - 5/9
  6. Subtract:                               -13/3 = -13/3

Here we see that -13/3 does indeed equal -13/3.

∴ u = -5/9 is a solution of the equation.

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