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ioda
3 years ago
10

Find the area of the circle given the following information. Give the exact answer and an approximation to the nearest tenth.

Mathematics
2 answers:
SpyIntel [72]3 years ago
8 0
A = 3.14 x r^2
= 3.14 x 6^2
= 3.14 x 36
= 103.62
goblinko [34]3 years ago
3 0

________________________________

<em>Hey</em><em>!</em><em>!</em><em>!</em><em>!</em><em> </em>

<h3><em>Sol</em><em>ution</em><em>,</em></h3>

<em>Diameter</em><em>=</em><em>1</em><em>2</em><em> </em><em>in</em>

<em>Radius</em><em>=</em><em>1</em><em>2</em><em>/</em><em>2</em><em> </em><em>=</em><em>6</em><em> </em><em>inch</em>

<em>Now</em><em>,</em><em> </em>

<em>Area</em><em> </em><em>of</em><em> </em><em>circle</em><em>=</em><em>pi</em><em> </em><em>r</em><em> </em><em>^</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>3</em><em>.</em><em>1</em><em>4</em><em>*</em><em>(</em><em>6</em><em>)</em><em>^</em><em>2</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>3</em><em>.</em><em>1</em><em>4</em><em>*</em><em>3</em><em>6</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>1</em><em>3</em><em>.</em><em>0</em><em>4</em><em> </em><em>inches^</em><em>2</em>

<h3><em>So</em><em> </em><em>the</em><em> </em><em>area</em><em> </em><em>of</em><em> </em><em>circle</em><em> </em><em>is</em><em> </em><em>1</em><em>1</em><em>3</em><em>.</em><em>0</em><em>4</em><em> </em><em>inches^</em><em>2</em><em>.</em></h3>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignmen</em><em>t</em>

<em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em><em>_</em>

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Write a differential equation that models the given situation. The stated rate of change is with respect to time t. (Use k for t
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The differential equation that models the given situation will be dy/dt = K(N - y).

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From the given statement, the rate for change will be t = dy/dt. Therefore, the differential equation that models the given situation will be dy/dt = K(N - y).

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