Help with what, unless there is a picture, my phone is glitchy and i cant see pics for sum reason
Answer:
Lcm is 30 and gcf is 1
Step-by-step explanation:
Trust me
Answer:
q = log4 / log0.53
q = -2.189
Step-by-step explanation:
(0.53)^q = 4
Taking log of both sides!
q log 0.53 = log 4
q = log 4 / log 0.53
q = 0.602 / -0.275
q = - 2.189
This can be checked to confirm correctness.
Substituting q = -2.189
(0.53)^ -2.189 = 1/ 0.249
= 4.01 Proved!
(Note that the "1" is because of the negative sign)
Answer:
20 m/s
Step-by-step explanation:
Assuming initial velocity is 0:
4m/s^2 * 5s = 20 m/s
Given:
To find:
The value of 
.
Solution:
We have,
Using properties of log, we get
![\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Clog_a%5Cdfrac%7Bm%7D%7Bn%7D%3D%5Clog_am-%5Clog_an%5Cright%5D)
![[\log x^n=n\log x]](https://tex.z-dn.net/?f=%5B%5Clog%20x%5En%3Dn%5Clog%20x%5D)
Substitute and .
Therefore, the value of is 
.
