<h3>Answer:</h3>
Yes, ΔPʹQʹRʹ is a reflection of ΔPQR over the x-axis
<h3>Explanation:</h3>
The problem statement tells you the transformation is ...
... (x, y) → (x, -y)
Consider the two points (0, 1) and (0, -1). These points are chosen for your consideration because their y-coordinates have opposite signs—just like the points of the transformation above. They are equidistant from the x-axis, one above, and one below. Each is a <em>reflection</em> of the other across the x-axis.
Along with translation and rotation, <em>reflection</em> is a transformation that <em>does not change any distance or angle measures</em>. (That is why these transformations are all called "rigid" transformations: the size and shape of the transformed object do not change.)
An object that has the same length and angle measures before and after transformation <em>is congruent</em> to its transformed self.
So, ... ∆P'Q'R' is a reflection of ∆PQR over the x-axis, and is congruent to ∆PQR.
Answer:
1)6x^2+7x-24
2) x-4
3) f(-3)=-14 g(-3)=2 f(-3)/g(-3)=-7 and p(-3)=-3-4=-7
f(-11)=90 g(-11)=-6 f(-11)/g(-11)=-15 and p(-11)=-11-4=-15
4)f'(x)=(x-7)/3
Step-by-step explanation:
1) f(x)=2x-3 g(x)=3x+8
f(x)*g(x)=m(x)=(2x-3)(3x+8)=6x^2+16x-9x-24=6x^2+7x-24
2) f(x)=x^2+x-20 g(x)=x+5
f(x)/g(x)=p(x)=(x^2+x-20)/(x+5)=> by finding the roots of f(x) we obtain =
(x-4)(x+5)/(x+5)--->f(x)/g(x)=p(x)=(x-4)
3) f(-3)=-14 g(-3)=2 f(-3)/g(-3)=-7 and p(-3)=-3-4=-7
f(-11)=90 g(-11)=-6 f(-11)/g(-11)=-15 and p(-11)=-11-4=-15
4) If a function f(x) is mapping x to y, then the inverse function of f(x) maps y back x
y=3x+7
(y-7)/3=x=--> f'(x)=(x-7)/3
Answer:
48a^7 b^5 (I hope I got this right, it has been awhile since I've done equations like these)
Step-by-step explanation:
(-4a^3 b^2)^2 × (3a^2 b)
16a^5 b^4 × 3a^2 b
48a^7 b^5
