We set up a proportion: ?/42,000= 3/5
Cross multiply:
5*?= 3*42,000
⇒ ?= 3*42,000/5= 25,200
3/5 of 42,000 is 25,200~
Answer:
is the number of graph edges which touch v
Step-by-step explanation:
To find the degree of a graph, figure out all of the vertex degrees. The degree of the graph will be its largest vertex degree. The degree of the network is 5.
Once you know the degree of the verticies we can tell if the graph is a traversable by lookin at odd and even vertecies. First lets look how you tell if a vertex is even or odd.
Answer:
A & C
Step-by-step explanation:
The equation for a circle is (x – h)^2 + (y – k)^2 = r^2, with the center being at (h,k). On the x-axis would mean the x coordinate would equal 0, therefore A and C are your answers.
Hope I helped! :)
These are two questions and two answers.
Question 1) Which of the following polar equations is equivalent to the parametric equations below?
<span>
x=t²
y=2t</span>
Answer: option <span>A.) r = 4cot(theta)csc(theta)
</span>
Explanation:
1) Polar coordinates ⇒ x = r cosθ and y = r sinθ
2) replace x and y in the parametric equations:
r cosθ = t²
r sinθ = 2t
3) work r sinθ = 2t
r sinθ/2 = t
(r sinθ / 2)² = t²
4) equal both expressions for t²
r cos θ = (r sin θ / 2 )²
5) simplify
r cos θ = r² (sin θ)² / 4
4 = r (sinθ)² / cos θ
r = 4 cosθ / (sinθ)²
r = 4 cot θ csc θ ↔ which is the option A.
Question 2) Which polar equation is equivalent to the parametric equations below?
<span>
x=sin(theta)cos(theta)+cos(theta)
y=sin^2(theta)+sin(theta)</span>
Answer: option B) r = sinθ + 1
Explanation:
1) Polar coordinates ⇒ x = r cosθ, and y = r sinθ
2) replace x and y in the parametric equations:
a) r cosθ = sin(θ)cos(θ)+cos(θ)
<span>
b) r sinθ =sin²(θ)+sin(θ)</span>
3) work both equations
a) r cosθ = sin(θ)cos(θ)+cos(θ) ⇒ r cosθ = cosθ [ sin θ + 1] ⇒ r = sinθ + 1
<span>
b) r sinθ =sin²(θ)+sin(θ) ⇒ r sinθ = sinθ [sinθ + 1] ⇒ r = sinθ + 1
</span><span>
</span><span>
</span>Therefore, the answer is r = sinθ + 1 which is the option B.
Answer: 91
Step-by-step explanation:
