one would say that the simple interest doubles if the period of time is specified in the contract and the contract is still valid, if the interest amount is available anitime and so on.
So if the amount doubles let's say at half time for which the principal was awarded to the bank, by the end of the contract , the interest amount can be double × just increased by 1.5
Answer:
8.22899353m
= 8m(round)
Step-by-step explanation:
14 * sin(36 degree) = 8.22899353
Answer:
43.96
Step-by-step explanation:warning might be wrong
Algebra:
A standard parabola is y = x^2. Its vertex is at (0,0)
You can change the position (or vertex) of the parabola.
To move a parabola across the x-axis, you can add or subtract a number from x WITHIN brackets of the ^2
eg. (x + 1)^2 will move the parabola across the x-axis. It will move is one unit to the LEFT (as the sign is opposite to the direction it moves ie. The sign it + but you move the whole parabola in the -ve direction).
Adding or subtracting a number from x OUTSIDE of the ^2 moves the parabola up or down the y-axis
eg. x^2 + 3 will move the parabola UP 3 units (the sign is the same as the direction it moves when the added/subtracted number is outside of the ^2 ie. the sign is positive so the parabola moves up in the positive direction)
From this, we can conclude that because (x + 1)^2 + 3, the vertex will be where x = -1 and where y = 3
Vertex : (-1,3)
Calculus:
f(x) = (x + 1)^2 + 3 = x^2 + 2x + 1 + 3 = x^2 + 2x + 4
Expanding the formular to make it easier to differentiate
f'(x) = 2x + 2
Differentiating (finding the formular the the gradiet of the parabola)
0 = 2x + 2
When the gradient is equal to zero, it must be the vertex
-2 = 2x
-2/2 = x
x = -1
Solve to give the x value at the vertex
f(x) = (x + 1)^2 + 3
= (-1 + 1)^2 + 3
Substitute x = -1 into original equatiom to find y value at the vertex
= (0)^2 + 3
= 0 + 3
= 3
Solve for y
Vertex : (-1,3)
Answer:
Tina is correct
Step-by-step explanation:
Given
Required
State if 
is a possible dimension
To do this, we simply expand
By comparison, the result of the expansion
and the given expression
are the same.
<em>Hence, Tina is correct</em>
