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MArishka [77]
3 years ago
8

A+2/a-5÷a+1/a2-8a+15

Mathematics
1 answer:
krok68 [10]3 years ago
3 0
For A+\frac{2}{a}-\frac{5}{a}+\frac{1}{a^2}-8a+15

Combine the fractions \frac{2}{a}  -  \frac{5}{a} \ \textgreater \  \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \  \frac{2-5}{a}


\mathrm{Subtract\:the\:numbers:}\:2-5=-3 \ \textgreater \  \frac{-3}{a}

\mathrm{Apply\:the\:fraction\:rule}:\ \frac{-a}{b}=-\frac{a}{b} \ \textgreater \  -\frac{3}{a}

Therefore our final answer is A-\frac{3}{a}+\frac{1}{a^2}-8a+15

Hope this helps!
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Suppose m = 2 + 6i, and | m + n | = 3√10, where n is a complex number.
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Step-by-step explanation:

first, the modulus of a complex number z = a + bi is

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The modulus of n must be equal to the square root of 50.

now we can find any values a and b such a^2 + b^2 = 50.

for example, a = 1 and b = 7

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